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Artist 52 [7]
3 years ago
11

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles.

Mathematics
1 answer:
diamong [38]3 years ago
8 0

Answer:

A.

\dfrac{6}{55}

B.

\dfrac{6}{55}

C.

\dfrac{4}{165}

Step-by-step explanation:

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles. There are 11 marbles in total.

A. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is red marble is

\dfrac{3}{10}

The probability that the first marble drawn is blue and the second is red is

\dfrac{4}{11}\cdot \dfrac{3}{10}=\dfrac{12}{110}=\dfrac{6}{55}

B. The probability that the first marble drawn is red marble is

\dfrac{3}{11},

the probability that the second marble drawn is white marble is

\dfrac{4}{10}

The probability that the first marble drawn is red and the second is white is

\dfrac{3}{11}\cdot \dfrac{4}{10}=\dfrac{12}{110}=\dfrac{6}{55}

C. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is blue marble is

\dfrac{3}{10},

the probability that the third marble drawn is blue marble is

\dfrac{2}{9},

The probability that the first, second and third marbles drawn are blue is

\dfrac{4}{11}\cdot \dfrac{3}{10}\cdot \dfrac{2}{9}=\dfrac{24}{990}=\dfrac{4}{165}

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