Answer:
result = 0
i = lo
while i <= hi:
result = result + i
i += 1
Explanation:
Initialize the <em>result</em> as 0 to hold the summation value.
Since we are asked not to change the value of <em>lo</em> and <em>hi</em>, our loop control variable is <em>i</em> and initially it starts from <em>lo.</em>
Since we are asked to add the number from <em>lo</em> to <em>hi, </em>while loop condition checks it.
While the condition satisfies (during each iteration), the value of <em>i</em> is added to the result and the value of <em>i</em> is incremented by one.
Answer:
public class Main
{
public static void main(String[] args) {
System.out.println(min(3, -2, 7));
}
public static int min(int n1, int n2, int n3){
int smallest = Math.min(Math.min(n1, n2), n3);
return smallest;
}
}
Explanation:
*The code is in Java.
Create a method named min that takes three parameters, n1, n2, and n3
Inside the method:
Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.
In the main:
Call the method with parameters given in the example and print the result
Answer:
The correct options is;
Every character written in A S C I I can be represented using Unicode
Explanation:
All characters found in A S C I I can be found in Unicode such that A S C I I is a subset of Unicode whereby the meaning of the numbers from 0 to 127 are the same in both A S C I I and Unicode
The size of the A S C I I character in 8-bit A S C I I encoding is 8 bits while a Unicode U T F - 8 encoding has between 8 bits (1 byte) and 32 bits (4-bytes)
A S C I I assigns only 127 of the 255 possible numbers that can be stored in an 8-bits character, where the spare characters are then used by P C s for accented characters, therefore, it A S C I I does not define accented characters
