Here's our equation.
We want to find out when it returns to ground level (h = 0)
To find this out, we can plug in 0 and solve for t.
So the ball will return to the ground at the positive value of
seconds.
What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!
Answer:
±i
Step-by-step explanation:
Observing that the first two coefficients are the same as the last two, we can factor this function by grouping.
f(x) = (x^3 -7x^2) +(x -7) = x^2(x -7) +1(x -7)
f(x) = (x^2 +1)(x -7)
The factor x-7 has a real zero at x=7, so the complex zeros come from the quadratic factor (x^2 +1).
Setting that to zero and solving for x, we find ...
x^2 +1 = 0
x^2 = -1
x = ±√(-1) = ±i
The complex zeros are x = +i and x = -i.
Answer:
m=-32
Step-by-step explanation:
-2=m/16
-2×16=m
-32=m
m=-32
The answer is 7. Hope it helps
since
6 = 2 * 3 <--- two factors
8 = 2 * 2 * 2 <--- three factors
and since the "2" is there on each, then we can just use that instance of it once.
so instead of using 2 * 3 * 2 * 2 * 2, we'll use 2 * 3 * 2 * 2, and that is our LCD.
2 * 3 * 2 * 2 = 24.