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svetoff [14.1K]
3 years ago
12

What is the metric unit that is used to describe weight as a measure of the force of gravity ?

Chemistry
2 answers:
masha68 [24]3 years ago
8 0
Newton

Hope this helped


Inessa [10]3 years ago
6 0
The metric unit that is used to describe weight as a measure of the force of gravity is called a Newton.
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Identifying the Reddish-Brown Substance (continued)
antiseptic1488 [7]

Here's link to the answer:

tinyurl.com/wpazsebu

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3 years ago
When electrons are added to the outter most shell of carbon atom it forms
GalinKa [24]

Answer:

An anion that has a larger radius.

Explanation:

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3 years ago
Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to c
jok3333 [9.3K]

Answer:

2.24 L of hydrogen gas, measured at STP, are produced.

Explanation:

Given, Moles of magnesium metal, Mg = 0.100 mol

Moles of hydrochloric acid, HCl = 0.500 mol

According to the reaction shown below:-

Mg_{(s)} + 2HCl_{(aq)}\rightarrow MgCl_2_{(aq)} + H_2_{(g)}

1 mole of Mg reacts with 2 moles of HCl

0.100 mol of Mg reacts with 2*0.100 mol of HCl

Moles of HCl must react = 0.200 mol

Available moles of HCl = 0.500 moles

Limiting reagent is the one which is present in small amount. Thus, Mg is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of Mg on reaction forms 1 mole of H_2

0.100 mole of Mg on reaction forms 0.100 mole of H_2

Mole of H_2 = 0.100 mol

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Volume = ?

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K  

<u>⇒V = 2.24 L</u>

2.24 L of hydrogen gas, measured at STP, are produced.

4 0
3 years ago
Which of these mixtures is a suspension?
natita [175]

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D. apple juice

Explanation:

8 0
3 years ago
A particular sample of pure iron requires 0.612 kJ of energy to raise its temperature from 30.°C to 51°C. What must be the mass
mixas84 [53]

Answer:

m = 65.637 g

Explanation:

Heat = 0.612 kJ = 612 J ( Converting to J by multiplying by 1000)

Initial Temperature =  30.°C

Final Temperature = 51°C

Temperature change = Final Temperature - Initial Temperature = 51 - 30 = 21°C

Mass = ?

The relationship between these quantities is given by the equation;

H = mCΔT

where c = 0.444 J/g°C

Inserting the values in the equation;

612 = m *  0.444 * 21

m = 612 / (0.444 * 21)

m = 65.637 g

3 0
3 years ago
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