Answer:
group 18 has 8 valence electrons, that's why they are stable.
Answer:
18.9 x 10¹³ grams of Bauxite Ore
Explanation:
Al₂O₃ = 50% of Bauxite Ore
Al₂O₃ = 0.5 (Bauxite Ore)--------------------------------------- (1)
Overall reaction:
2Al₂O₃ + 3C → 4Al + 3CO₂--------------------------------------- (2)
[ Al= 27 , O=16, C=12]
From (2), 2 moles of Aluminium oxide (Al₂O₃) gives 4 moles of Aluminium
In terms of grams, we can say:
Al₂O₃ = [2(27) +3(16)]
= 54 +48
=102grams
2 moles of Al₂O₃ = 2 x102grams
=204grams
4 moles of Al = 4 x 27
=108 grams
So from (2):
204 grams of Al₂O₃ = 108 grams of Aluminium
x grams of Al₂O₃ = 5.0 x 10¹³grams of Aluminium
Calculating for x:
x = (204 x 5.0 x 10¹³)/ 108
= 9.44 x 10¹³ grams
So 9.44 x 10¹³ grams of pure bauxite (Bauxite) is required.
However the to calculate the quantity of raw bauxite, we use (1):
Bauxite ore = Pure Bauxite/0.5
= 9.44 x 10¹³ grams/0.5
= 18.88 x 10¹³ grams
≈ 18.9 x 10¹³ grams
2 hydrogen and 2 chlorine on the reactant side(left of the arrow)
There is only 1 H and 1Cl on the products side so the balanced equation would be;
H2 + Cl2 —> 2 HCl
Freezing Point of Sea water would be lower than that of Pure Water. It is because of salinity of the water
Hope this helps!
