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BlackZzzverrR [31]
2 years ago
12

Which of these mixtures is a suspension?

Chemistry
1 answer:
natita [175]2 years ago
8 0

Answer:

D. apple juice

Explanation:

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Hope it helped you.

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3 years ago
A pulse with an amplitude of 3+ would be considered:
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<span>A pulse with an amplitude of 3+ would be considered as increased. Peripheral Pulse Assessment Grading System is measured in 0 - 3 Scale. 0 = absent 1+ = Weak/thready pulse 2+ Normal Pulse 3+ = Full, firm pulse. from the above scale we can find that the 3+ reading shows that the pulse is increased.</span>
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How many molecules are present in the following quantity<br> 0.250 mole of H2O
klio [65]
If  1mole ------------- is ---------------- 6.02*10²³
than 0.25mole ----- is ----------------  x

x = [0.25mole*6.02*10²³]/1mole = <u>1,505*10²³</u>
4 0
3 years ago
What is the molarity of a solution that contains 2 moles of solute in 4 liters of solution?
Nitella [24]
The simple formula is C = n/V
n = mols
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V = Volume in Liters.

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8 0
3 years ago
Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit
rosijanka [135]

Explanation:

The relation between K_a\&K_b is given by :

K_w=K_a\times K_b

Where :

K_w=1\times 10^{-14} = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = K_{a1}=1.4\times 10^{-2}

The value of K_{b1}:

1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}

The value of the second ionization constant of sodium sulfite = K_{a2}=6.3\times 10^{-8}

The value of K_{b2}:

1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}

3 0
3 years ago
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