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DiKsa [7]
3 years ago
11

Where is the genetic code located again in the dna molecule again?

Chemistry
1 answer:
Pie3 years ago
8 0

Answer:

The DNA is in the nucleus.

Explanation:

The nucleus is the power house of the cell, the little sting things inside are the strands of DNA.

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The diagram shows the movement of particles from one end of the container to the opposite end of the container.
Aleksandr-060686 [28]
The correct option is this: EFFUSION BECAUSE THERE IS A MOVEMENT  OF A GAS THROUGH A SMALL OPENING INTO A LARGER VOLUME.
Effusion refers to the movement of gas particles through a small hole. According to Graham's law, the effusion rate of a gas is inversely proportional to the square root of the mass of its particles.

7 0
3 years ago
Read 2 more answers
11 Which substance can not be broken down by a chemical change?
Rus_ich [418]
(2) Arsenic. It is an element and elements are chemically the simplest units and cannot be broken down by any chemical change.
4 0
3 years ago
Question 6 (1 point)
Mnenie [13.5K]

Answer:

The correct option is;

d 4400

Explanation:

The given parameters are;

The mass of the ice = 55 g

The Heat of Fusion = 80 cal/g

The Heat of Vaporization = 540 cal/g

The specific heat capacity of water = 1 cal/g

The heat required to melt a given mass of ice = The Heat of Fusion × The mass of the ice

The heat required to melt the 55 g mass of ice = 540 cal/g × 55 g = 29700 cal

The heat required to raise the temperature of a given mass ice (water) = The mass of the ice (water) × The specific heat capacity of the ice (water) × The temperature change

The heat required to raise the temperature of the ice from 0°C to 100°C = 55 × 1 × (100 - 0) = 5,500 cal

The heat required to vaporize a given mass of ice = The Heat of Vaporization × The mass of the ice

The heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal

The total heat required to boil 55 g of ice = 29700 cal + 5,500 cal + 4,400 cal = 39,600 cal

However, we note that the heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal.

The heat required to vaporize the 55 g mass of ice at 100°C = 4,400 cal

3 0
3 years ago
How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?
Semenov [28]
Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!
3 0
3 years ago
Read 2 more answers
2NaCl + F2 yields 2NaF + Cl2
bearhunter [10]
Study your experiment setup.<span> In 30 minutes, how will the air temperature in the bottles compare?</span><span> What do you predict will happen to the ice in each bottle?</span>
7 0
3 years ago
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