A spring that is stretched by hanging a 5kg mass. It's equilibrium length was 0.5 meters. Now the length of the spring is 1.6 me
ters. What is the spring constant?
1 answer:
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Answer:
0.82 m
Explanation:
The ball is in free fall - uniform accelerated motion with constant acceleration downward, (acceleration of gravity). So we can use the following suvat equation to solve the problem:
where
v is the final velocity
u = 4 m/s is the initial velocity
a is the acceleration
s is the displacement
At the maximum displacement, v = 0 (the velocity becomes zero). Substituting and solving for s, we find: