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Rainbow [258]
3 years ago
8

Which statement best describes the adiabatic process?

Physics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Answer:

A:  In an adiabatic process, no heat enters or leaves the system

kupik [55]3 years ago
4 0

Answer:

diaetes

Explanation:

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HELP ASAP!! WILL TRY TO GIVE BRAINLIEST
VikaD [51]

Answer:

Facilitated diffusion and active transport both utilize proteins to transport substances across membranes. Differences between active transport and facilitated diffusion 1. Active transport requires an input of energy, usually ATP, while facilitated transport does not.

5 0
3 years ago
what would you want the after life to be like. examples are heaven and hell ,reincarnation ,eternal darkness , reliving your liv
NeTakaya

Answer:

i would want to be a dog or a cat

Explanation:

there just funny

4 0
3 years ago
A gas is placed in a storage tank at a pressure of 49.2 atm at 39.0C . As a safety device, a small metal plug in the tank is mad
Amiraneli [1.4K]

Answer:

The maximum pressure that will be attained in the tank before the plug melts and releases gas should be less than 74.26 atm.

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=49.2 atm\\T_1=39.0^oC = 312.15 K\\P_2=?\\T_2=198^oC=471.15 K

Putting values in above equation, we get:

\frac{49.2atm }{312.15 K}=\frac{P_2}{471.15 K}\\\\P_2=74.26 atm

The maximum pressure that will be attained in the tank before the plug melts and releases gas should be less than 74.26 atm.

4 0
3 years ago
How many amps are there in the current of a circuit if the voltage source is 140v and the resistance is 2 ohms?
VLD [36.1K]
Voltage (V)= Current (I) * Resistance (R)
I=V/R=140/2=70A

Hope this helps!
7 0
3 years ago
Assume that the polymer material has a constant refractive index of 1.5. For light of 600nm wavelength at normal incidence, what
yaroslaw [1]

Answer:

Minimum thickness will be 100 nm

Explanation:

We have given refractive index is n = 1.5

Wavelength of the light incidence \lambda= 600 nm

We have to find the smallest thickness of the film so that there will be minimum light reflect

For minimum thickness of non reflecting film

t=\frac{\lambda }{4n} , here t is thickness, \lambda is wavelength and n is refractive index

Putting all values t=\frac{600}{4\times 1.5}=100nm

So minimum thickness will be 100 nm

8 0
3 years ago
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