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solniwko [45]
3 years ago
11

The sum of two or more vectors is called a vector. Answer kere

Physics
2 answers:
Sonbull [250]3 years ago
8 0

Answer:

Resultant vector is the sum of two or more vectors

zhenek [66]3 years ago
3 0

Kere you are:

The sum of two or more vectors is called a  <em>resultant</em> vector.

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You place a box weighing 200.2 N on a inclined plane that makes a 37.1 angle with the horizontal. Compute the component of the g
salantis [7]

Answer:

141.56 N.

Explanation:

Data given:

Weight of the box= 200.2 N

Angle with the horizontal= 37.1°

Solution;

Gravitational force on the box, F_g= weight of the box

                                                                           = 200.2 N

Component of gravitational force along plane = F_g * sin( ∅ )

                                                                                   = W * (sin∅)

                                                                                   = (200.1) * sin (37.1°)

                                                                                   = 141.56 N

8 0
3 years ago
An electron and a 0.033 0-kg bullet each have a velocity of magnitude 495 m/s, accurate to within 0.010 0%. Within what lower li
lara31 [8.8K]

Answer:

1.170*10^-3 m

3.23*10^-32 m

Explanation:

To solve this, we apply Heisenberg's uncertainty principle.

the principle states that, "if we know everything about where a particle is located, then we know nothing about its momentum, and vice versa." it also can be interpreted as "if the uncertainty of the position is small, then the uncertainty of the momentum is large, and vice versa"

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

If we make Δx the subject of formula, by rearranging, we have

Δx = h / 4π * m(e).Δv

on substituting the values, we have

for the electron

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 5.67*10^-31

Δx = 1.170*10^-3 m

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.033*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 0.021

Δx = 3.23*10^-32 m

therefore, we can say that the lower limits are 1.170*10^-3 m for the electron and 3.23*10^-32 for the bullet

7 0
3 years ago
Quick Physics Question
sveticcg [70]
It is Real,Virtual,The Same Size, Inverted
8 0
3 years ago
When a carousel is in motion, the movement of the carousel horse can best be described as?
tatiyna
Supposing the carousel is rotating with constant speed, the movement is uniform angular motion.
5 0
3 years ago
A stoplight with weight 100 N is suspended at the midpoint of a cable strung between two posts 200 m apart. The attach points fo
Tasya [4]

There are 3 forces acting on the stoplight:

• its weight <em>W</em>, with magnitude <em>W</em> = 100 N, pointing directly downward

• two tension forces <em>T</em>₁ and <em>T</em>₂ with equal magnitude <em>T</em>₁ = <em>T</em>₂ = <em>T</em> = 1000 N, both making an angle of <em>θ</em> with the horizontal, but one points left and the other points right

The stoplight is in equilibrium, so by Newton's second law, the net vertical force acting on it is 0, such that

∑ <em>F</em> = <em>T</em>₁ sin(<em>θ</em>) + <em>T</em>₂ sin(180° - <em>θ</em>) - <em>W</em> = 0

We have sin(180° - <em>θ</em>) = sin(<em>θ</em>) for all <em>θ</em>, so the above reduces to

2<em>T</em> sin(<em>θ</em>) = <em>W</em>

2 (1000 N) sin(<em>θ</em>) = 100 N

sin(<em>θ</em>) = 0.05

<em>θ</em> ≈ 2.87°

If <em>y</em> is the vertical distance between the stoplight and the ground, then

tan(<em>θ</em>) = (15 m - <em>y</em>) / (100 m)

Solve for <em>y</em> :

tan(2.87°) = (15 m - <em>y</em>) / (100 m)

<em>y</em> = 15 m - (100 m) tan(2.87°)

<em>y</em> ≈ 9.99 m

3 0
3 years ago
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