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GuDViN [60]
3 years ago
12

You move a box 5 meters and perform 900 joules of work. How much force did you apply to the box?

Physics
1 answer:
valkas [14]3 years ago
7 0

Answer:

180 N

Explanation:

Work = force × distance

900 J = F × (5 m)

F = 180 N

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A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative r
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Answer:

The workdone is  W = 1.712 *10^{-20 } \  J  

Explanation:

From the question we are told that

    The potential difference is  V  =  107 mV =  107 *10^{-3} \  V

Generally the charge on  Na^{+} is  Q_{Na^{+}} = 1.60 *10^{-19 } \  C

 Generally the workdone is mathematically represented as

         W =  Q_{Na^{+}}V

=>     W = 1.60 *10^{-19 } *  107 *10^{-3}    

=>     W = 1.712 *10^{-20 } \  J    

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