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3 years ago

12

You move a box 5 meters and perform 900 joules of work. How much force did you apply to the box?

1 answer:

valkas [14]3 years ago

7 0

Answer:

180 N

Explanation:

Work = force × distance

900 J = F × (5 m)

F = 180 N

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Who was the first person referred to as a psychologist?

musickatia [10]

Answer:

Wilhelm Wundt

Explanation:

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3 years ago

Two scales on a nondigital voltmeter measure voltages up to 20.0 and 30.0 V, respectively. The resistance connected in series wi

Snowcat [4.5K]

Answer:

Resistance of the circuit is 820 Ω

Explanation:

Given:

Two galvanometer resistance are given along with its voltages.

Let the resistance is "R" and the values of voltages be 'V' and 'V1' along with 'G' and 'G1'.

⇒ $V=20\ \Omega,\ V_1=30\ \Omega$

⇒ $G=1680\ \Omega,\ G_1=2930\ \Omega$

Concept to be used:

Conversion of galvanometer into voltmeter.

Let $G$ be the resistance of the galvanometer and $I_g$ the maximum deflection in the galvanometer.

To measure maximum voltage resistance $R$ is connected in series .

So,

⇒ $V=I_g(R+G)$

We have to find the value of $R$ we know that in series circuit current are same.

For $G=1680$ For $G_1=2930$

⇒ $I_g=\frac{V}{R+G}$ equation (i) ⇒ $I_g=\frac{V_1}{R+G_1}$ equation (ii)

Equating both the above equations:

⇒ $\frac{V}{R+G} = \frac{V_1}{R+G_1}$

⇒ $V(R+ G_1) = V_1 (R+G)$

⇒ $VR+VG_1 = V_1R+V_1G$

⇒ $VR-V_1R = V_1G-VG_1$

⇒ $R(V-V_1) = V_1G-VG_1$

⇒ $R =\frac{V_1G-VG_1}{(V-V_1)}$

⇒ Plugging the values.

⇒ $R =\frac{(30\times 1680) - (20\times 2930)}{(20-30)}$

⇒ $R =\frac{(50400 - 58600)}{(-10)}$

⇒ $R=\frac{-8200}{-10}$

⇒ $R=820\ \Omega$

The coil resistance of the circuit is 820 Ω .

4 0

3 years ago

One mole of an ideal gas does 3000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and

taurus [48]

Answer:

(a) Initial volume will be 7.62 L

(b) Final temperature will be 303.85 K

Explanation:

We have given one mole of ideal gas done 3000 J

So work done W = 3000 J

Let initial volume is $V_1$ and initial pressure $P_1=1atm$ ( As pressure is constant )

Final volume $V_2=25L$ = 0.025 $m^3$

Number of moles n = 1

(B) From ideal gas of equation we know that $PV=nRT$

So $1.01\times 10^5\times0.025=1\times 8.31\times T$

T = 303.85 Kelvin

(B) For isothermal process work done is equal to

$W=nRTln\frac{V_2}{V_1}$

$3000=1\times 8.314\times 303.85\times ln\frac{0.025}{V_1}$

$ln\frac{0.025}{V_1}=1.1881$

$\frac{0.025}{V_1}=3.2808$

$V_2=0.00846m^3=7.62L$

So initial volume will be 7.62 L

5 0

3 years ago

A 13-N east horizontal force acts in the same direction as a 6.4kg block as it slides 2.5m/s on a frictionless, horizontal surfa

MaRussiya [10]

Answer:

6.77 m/s

Explanation:

Acceleration = Force/mass;

The block is accelerated by 13/6.4 m/s^2 for 2.1s from an initial velocity of 2.5m/s.

Applying the equation of motion:

Vf=Vi + at

Where Vf is the final velocity, Vi is the initial velocity, a is the acceleration and t is the time for which the object accelerates.

<h3>Vf= 2.5 + ((13/6.4)*2.1);</h3>

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3 years ago

Tim, with mass 53.5 kg, climbs a gymnasium

Stella [2.4K]

Potential energy = mgh

= 53.5 x 9.8 x 4.7

= 2464.21 Joules

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2 years ago