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2 years ago

The weight of a rock sample is measured to be 2.5 pounds. What is the percent of error in the measurement? 2% 5% 10%

Mathematics

1 answer:

elixir [45]2 years ago

6 0

Answer:

The percent of error in the measurement is 2%

Step-by-step explanation:

The percent of error associated with a reported measurement is calculate using the formula;

$percenterror=\frac{error}{measurement}*100$

The error associated with a measurement is defined as half of the smallest unit of measurement used. The measurement reported was 2.5. The smallest unit of measurement for this reading is 0.1. The error is thus;

error = 0.1/2 = 0.05

The percent of error is thus;

$\frac{0.05}{2.5}*100=2$

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$w=\frac { 4 }{ 5 } \cdot l$ , we can plug w's value in the previous equation to find "l".

$\frac { 4 }{ 5 } \cdot l\cdot l=320\\ \\ \frac { 4 }{ 5 } \cdot { l }^{ 2 }=320\\ \\ { l }^{ 2 }=320\cdot \frac { 5 }{ 4 } \\ \\ { l }^{ 2 }=\frac { 320\cdot 5 }{ 4 } \\ \\ { l }^{ 2 }=\frac { 1600 }{ 4 } \\ \\ { l }^{ 2 }=400\\ \\ \sqrt { { l }^{ 2 } } =\sqrt { 400 } \\ \\ l=20$

Let's plug "l"s value in the equation.

$w.l=320\quad \Longrightarrow \quad w\cdot 20=320\quad \Longrightarrow \quad w=\frac { 320 }{ 20 } \quad \Longrightarrow \quad w=16$

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