The unbalanced chemical equation with the corresponding phase for each substance is shown below:
Cu₍s₎ + H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + H₂O₍l₎
The copper metal is solid, the sulfuric acid and copper sulfate are in aqueous solution. Water is in the liquid phase while sulfur dioxide is in the gas phase.
In order to obtain the balanced equation, we must ensure that the number of atoms present in the reactant side is equal to that in the product side. First, we list the elements involved and count their number on each side.
Reactant Product
1 Cu 1
2 H 2
1 S 2
4 O 5
To balance the equation, we need to have 2 moles of H₂SO₄ and 2 moles of H₂O. The balanced chemical equation is then:
Cu₍s₎ + 2H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + 2H₂O₍l₎
Reactant Product
1 Cu 1
4 H 4
2 S 2
8 O 8
Answer:
Cp = 0.093 J.g⁻¹.°C⁻¹
Solution:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 300 J
m = mass = 267 g
Cp = Specific Heat Capacity = ??
ΔT = Change in Temperature = 12 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 300 J / (267 g × 12 °C)
Cp = 0.093 J.g⁻¹.°C⁻¹
Answer: 35.4 g
2 moles of phosphorous chloride are produced by = 3 moles of
Thus 0.37 moles of phosphorous chloride are produced by= of
Mass of
Thus 35.4 g of chlorine reacted with the phosphorus
They are called dry cells because the electrolyte is a paste.
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