Answer:v nxfgdjngdnmgndjfnncnfndngndsnbxzmnfn
Explanation:
Answer:

Explanation:
Potential energy is minus the integral of Fdx. Doing the integration yields:



so


Now for x=3.0m


Solid has vibrating molecules that barely move to keep it's shape
liquid moves at an average speed and keeps it's volume but not it's shape
gases move quickly and all over the place so they don't have a shape or volume
plasma is the quickest moving and is like a gas
Answer:
a. 3.039cm
b.magnetic field is 
Explanation:
Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:

Angle of net magnetic field from axial direction is given by:
,
Field due to solenoid:

Field due to wire:

Therefore, r:

Hence, the radial distance is 3.039cm
b.The magnetic field strength is given by:

Hence, the magnetic field is 
A wave carries energy from a source to a point some distance away. A wave is reflected by a barrier. The reflected wave moves away from the barrier at an angle that is equal to the angle with which the incoming wave moved towards the barrier. When a wave is slowed down, it refracts—that is, changes direction.