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GREYUIT [131]
3 years ago
10

When heat is added to an object, what is happening to the item at the atomic level? (Check all that apply)

Physics
2 answers:
3241004551 [841]3 years ago
6 0

Answer:

a

Explanation:

heat is energy, energy cannot be made or destroyed but transferred

Fofino [41]3 years ago
3 0

Answer:

At atomic level, the following is happening:

  • The atoms in the structure are vibrating more
  • The atoms begin to move more

Explanation:

When heat is added to an object the kinetic energy of its atoms is increased. That makes the atoms to vibrate more and to move more.

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At a height of ten meters above the surface of a freshwater lake, a sound pulse is generated. The echo from the bottom of the la
konstantin123 [22]

Answer:

Explanation:

Velocity of sound in air at 20 degree = 343 m/s

Velocity of sound in water at 20 degree = 1470 m/s

Time taken in to and fro movement in air

=( 2 x 10) / 343 = 0.0583 s

Rest of the time  is

.171 - .0583 = .1127 s

This time is taken to cover distance in water. If d be the depth of lake

2d / velocity = time taken

2 d / 1470 = .1127

d = 82.83 m

5 0
3 years ago
Work done in taking charge from one point of a conductor to is another point is called ​
Yuliya22 [10]

Answer:

⁸

Explanation:

electric potential

I think so

6 0
3 years ago
What is the purpose of the Climate Friendly Farming Project?
blsea [12.9K]
<span>The Climate Friendly Farming Project was designed to provide funding for long term research into the sustainability and adaptability of agricultural systems(wheat, vegetables, and dairy systems) as increasing greenhouse gases propagate and decline the efficiency of current agricultural practice.</span>
4 0
3 years ago
For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

where,

N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

thus,

V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

4 0
3 years ago
Read 2 more answers
water is pumped from a stream at the rate of 90kg every 30s and sprayed into a farm at a velocity of 15m/s. Calculate the power
nikitadnepr [17]

Answer:

340 W

Explanation:

Power = change in energy / change in time

P = ΔKE / Δt

P = ½ mv² / Δt

P = ½ (90 kg) (15 m/s)² / (30 s)

P = 337.5 W

Rounded to 2 significant figures, the power is 340 W.

7 0
3 years ago
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