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Alika [10]
3 years ago
13

A bullet is fired in a horizontal direction with a muzzle velocity of 300m/s.In the absence of air resistance,how far will it ha

ve droppped in travelling a horizontal distance of how far it will drop one one second
Physics
1 answer:
Kruka [31]3 years ago
6 0

Answer:

304.9m

Explanation:

Given

Velocity = 300m/s

Tim = 1sec

Required

Horizontal distance S

Using the formula

S= ut+1/2gt²

S = 300(1)+1/2(9.8)(1)²

S = 300+4.9

S = 304.9m

Hence the distance travelled is 304.9m

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<h3>Velocity ratio of the screw</h3>

The velocity ratio of the screw is calculated as follows;

V.R = 2πr/P

where;

  • P is the pitch = 1/10 cm = 0.1 cm = 0.001 m
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V.R = (2π x 0.25)/(0.001)

V.R = 1570.8

<h3>Mechanical advantage of the screw</h3>

E = MA/VR x 100%

0.5 = MA/1570.8

MA = 785.39

Learn more about mechanical advantage here: brainly.com/question/18345299

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