Answer:
Explanation:
The volume of contaminated water
= cross sectional area x height of water level
3.14 x 9 x 9 x 7.5 ft³
= 1907.55 ft³
mass = density x volume
= 1907.55 x 63.5 lbs
m = 121129.425 lbs
This mass has to be raised to the height of 8 ft before evacuation .
There is a rise of centre of mass of
8 - 7.5/2 ft
h = 4.25 ft
Energy required
= mgh
= 121129.425 x 32 x 4.25
= 16473601.8 unit.
Answer:
THES IS NOT
Explanation:
THIS PAPAER IS A FAKE PAPAER BEACISE POGI TALAGA AKO
The variable would be “X”
Is this a true or false question?
Answer:
3.6ft
Explanation:
Using= 2*π*sqrt(L/32)
To solve for L, first move 2*n over:
T/(2*π) = sqrt(L/32)
Next,eliminate the square root by squaring both sides
(T/(2*π))2 = L/32
or
T2/(4π2) = L/32
Lastly, multiply both sides by 32 to yield:
32T2/(4π2) = L
and simplify:
8T²/π²= L
Hence, L(T) = 8T²/π²
But T = 2.1
Pi= 3.14
8(2.1)²/3.14²
35.28/9.85
= 3.6feet
