Answer:
i'm confused is it asking what 64-28 is
Step-by-step explanation:
Answer:
680
Step-by-step explanation:
Use the binomial coefficient where you choose 
numbers out of 
possible numbers and find the total amount of combinations since order does not matter:
Thus, you can make 680 three-non-repeating-number codes
Answer:
It's not possible.
Step-by-step explanation:
The center of the star shape is like a circle. And the measure of a circle is 360 degrees. But because the measure of the rhombus's angle is 50 degrees, it is not possible. 50 x 8 = 400
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2
