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Murrr4er [49]
3 years ago
10

Identify which sets of quantum numbers are valid for an electron. Each set is ordered (n,l,ml,ms).a. 3,1,1,-1/2b. 4,3,1,-1/2c. 2

,0,0,-1/2d. 1,3.0,1/2e. 3,2,-1,-1/2f. 3,3,-1,1/2g. 3,2,1,-1h. 1,-1,-1,-1/2i. 3,3,1,1/2j. 3,0,0,1/2k. 4,3,4,-1/2l. 0,2,1,1/2
Chemistry
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

The valid set of quantum numbers are:

a. 3,1,1,-1/2

b. 4,3,1,-1/2

c. 2,0,0,-1/2

e. 3,2,-1,-1/2

j. 3,0,0,1/2

Explanation:

Quantum numbers (n, l, mℓ, ms) are the set of numbers that describe the state of an electron in an atom.

<u>The four quantum numbers and their rules are</u>:

  1. Principal: n ≥ 1  
  2. Azimuthal: ℓ ≤ (n-1)
  3. Magnetic: mℓ = (- ℓ) to (+ ℓ)
  4. Spin: ms = (- s), (+ s)  

Therefore,

a. 3,1,1,-1/2: <em>Valid</em>

b. 4,3,1,-1/2: <em>Valid</em>

c. 2,0,0,-1/2: <em>Valid</em>

d. 1,3,0,1/2: <u>NOT</u> <em>Valid</em>

<u>Reason</u>: ℓ ≤ (n-1). Therefore, ℓ can not be greater than n, .

e. 3,2,-1,-1/2: <em>Valid</em>

f. 3,3,-1,1/2: <u>NOT</u><em> Valid</em>

<u>Reason:</u> ℓ ≤ (n-1). Therefore, ℓ can not be equal to n. (ℓ ≠n)

g. 3,2,1,-1: <u>NOT</u> <em>Valid</em>

Reason: the only allowed values of ms = (- s), (+ s) = (- 1/2), (+ 1/2)

h. 1,-1,-1,-1/2: <u>NOT </u><em>Valid</em>

<u>Reason</u>: ℓ ≤ (n-1) and n ≥ 1. Therefore, ℓ can not be equal to n and also ℓ can't be negative.

i. 3,3,1,1/2: <u>NOT </u><em>Valid</em>

<u>Reason:</u> ℓ ≤ (n-1). Therefore, ℓ can not be equal to n. (ℓ ≠n)

j. 3,0,0,1/2: <em>Valid</em>

k. 4,3,4,-1/2: <u>NOT </u><em>Valid</em>

<u>Reason</u>: mℓ = (- ℓ) to (+ ℓ). Therefore, mℓ can't be greater than ℓ.

l. 0,2,1,1/2: <u>NOT </u><em>Valid</em>

<u>Reason:</u> n ≥ 1. Therefore, value of n can't be 0 (n≠0)

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