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3 years ago

11

When dissolved sodium hydroxide reacts with hydrogen sulfate, aqueous sodium, sulfate, water, and heat are formed. Write out the

balanced equation for this
reaction and indicate what the coefficients are from left to right. (Note: Be sure to
keep the reactants and products in the same order that they appear in the
question.)

a) 2,1,1,2
b) 4,2,2,4
c) 1,1,1,1
d) 1,2,2,1

1 answer:

nignag [31]3 years ago

4 0

Answer:

2 NaOH(aq) + H2SO4(aq) ⇒ Na2SO4 (aq) + 2 H2O(l)

Explanation:

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Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$

(2) $XCl_4(s)\rightarrow X(s)+2Cl_2(g)$ $\Delta H_2=-461.9kJ$

(3) $2H_2(g)+2Cl_2(g)\rightarrow 4HCl(g)$ $\Delta H_3=4\times -92.3kJ=-369.2kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $2H_2O(l)\rightarrow 2H_2O(g)$ $\Delta H_5=2\times 44.0kJ=88.0kJ$

The expression for enthalpy of main reaction will be:

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4+\Delta H_5$

$\Delta H=(483.6)+(-461.9)+(-369.2)+(-789.1)+(88.0)$

$\Delta H=-1048.6kJ$

Therefore, the enthalpy of the given reaction will be, -1048.6 kJ

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3 years ago

Which of the following describes the location and energy of all the valence electrons

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Answer:

1s22s22p6<u>3s23p4</u>

Explanation:

Sulfur is located in the p block and has 6 valence electrons (the 2 exponent on the 3s and the 4 exponent on the 3p add up to 6)

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Why is it difficult to hold and keep liquids like water in your hand? Guys please help

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Is the production of nitrogen(II) oxide exothermic or endothermic?

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Calculate how many grams of of copper sulfate pentahydrate are required to prepare

Rzqust [24]

Molar mass CuSO4.5H2<span>O => 249.685 g/mol

Volume in liters => 100 mL / 1000 => 0.1 L
</span>
1 L ----------------- 0.05 M
0.1 L -------------- ?? ( moles of <span>copper sulfate pentahydrate )
</span>
0.1 x 0.05 / 1 => 0.005 moles

1 mole ------------- <span> 249.685 g
</span>0.005 moles ------- ( mass of <span>copper sulfate pentahydrate )
</span>
0.005 x 249.685 / 1 => 1.28425 g CuSO4.5H2<span>O
</span>
hope this helps!

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