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3 years ago

Transduction of lower frequency sound waves occurs at the __________ of the cochlea.

Physics

2 answers:

goldenfox [79]3 years ago

7 0

the answer choices are base, proximal end, middle and apex.

the correct answer is apex.

kiruha [24]3 years ago

4 0

I got inner ear for my answer if wrong sorry

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An electric drag racer is much like its piston engine counterpart, but instead it is powered by an electric motor running off of

Lapatulllka [165]

Answer:

5.5879 m/s²

0.56961g

149.9976 mph

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement = 0.25 miles

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow 0.25\times 1609.34=0\times t+\frac{1}{2}\times a\times 12^2\\\Rightarrow a=\dfrac{0.25\times 1609.34\times 2}{12^2}\\\Rightarrow a=5.5879\ m/s^2$

The acceleration is 5.5879 m/s²

Dividing by g

$\dfrac{a}{g}=\dfrac{5.5879}{9.81}\\\Rightarrow a=0.56961g$

The acceleration of these cars is 0.56961 times g

$v=u+at\\\Rightarrow v=0+5.5879\times 12\\\Rightarrow v=67.0548\ m/s$

Converting mph

$67.0548\times \dfrac{3600}{1609.34}=149.9976\ mph$

The speed is 149.9976 mph

6 0

3 years ago

A 1.34 kg ball is connected by means of two massless strings, each of length L 1.70 m, to a vertical, rotating rod. The strings

zheka24 [161]

Answer:

The ball and the strings are shown in the attached figure

Balancing the forces in Y direction we have

$35sin(\theta )=1.34\times 9.81+T_{2}sin(\theta )\\\\sin(\theta )=\frac{0.85}{1.7}=0.5\\\\\therefore T_{2}=\frac{35sin(\theta )-13.14N}{sin(\theta )}\\\\T_{2}=8.72N$

The magnitude of net force on ball in

1) Y direction is zero since there is no acceleration of ball along y direction.

2)In x direction is given by $35cos(30)+T_{2}cos(30)=37.88N$

The force in the x direction provides centripetal acceleration for the ball thus we have

$35cos(30)+T_{2}cos(30)=37.88N\\\\37.88=\frac{mv^{2}}{r}\\\\\therefore v=\sqrt{\frac{37.88\times r}{m}}\\\\r=1.70cos(30)=1.47m\\\\\therefore v=\sqrt{\frac{37.88\times 1.47}{1.34}}=6.44m/s\\\\$

8 0

3 years ago

Compared to the wavelength of incident light, diffuse reflection occurs when the size of surface irregularities is?

bagirrra123 [75]

Compared to the wavelength of the incident light, diffuse reflection occurs when the size of surface irregularities is comparable to the size of the wavelength of the light.

The distance between the two crests or troughs of the light wave is known as the wavelength of light. Using the Greek letter lambda 'λ', it is identified. As a result, wavelength refers to the separation between one wave's crest or dip and the following wave.

In contrast to specular reflection, diffuse reflection involves the reflection of light, other waves, or particles off a surface so that rays incident on the surface are scattered at a variety of angles.

Refer to more about wavelength here

brainly.com/question/13533093

#SPJ4

5 0

1 year ago

Consider a skateboarder who starts from rest at the top of ramp that is inclined at an angle of 18.0 ∘ to the horizontal.

kotegsom [21]

Answer:

Explanation:

v= u + at

v is final velocity , u is initial velocity . a is acceleration and t is time

Initial velocity u = 0 . Putting the given values in the equation