Answer:
875 N
Explanation:
From this question, you didn't state the time taken for the bumper car to move or to hit the other bumper car. In calculations of force, time is often needed, because
Force = mass * acceleration, while
Acceleration = velocity / time, basically
Force = mass * velocity / time.
We have our mass, we have our velocity, but we haven't time. So, for this calculation, I'd assume our time to be 1s.
Going by the formula I stated, we can then say that
Force = 250 * 3.5 / 1
Force = 875 N
This means the force my bumper car have while moving at 3.5 m/s for an estimated time of 1s is 875 N
Answer:
v= 3.18 m/s
Explanation:
Given that
m= 150 g = 0.15 kg
M= 240 g = 0.24 kg
Angular speed ,ω = 150 rpm
The speed in rad/s
ω = 15.7 rad/s
The distance of center of mass from 150 g
r= 20.30 cm
The speed of the mass 150 g
v= ω r
v= 20.30 x 15.7 cm/s
v= 318.71 cm/s
v= 3.18 m/s
<span>stuntman's vertical velocity is
vy= 6 sin 15=1.55m/s.
Height that he goes up is,
vertical kinetic energy = mgh
1/2 v² = gh, h=v²/(2g)=0.12 m.
time wanted to go up= vy/9.8=0.16s, Time to fall through a height
0.12+2.9=3.02m is
t=sqrt(3.02*2/9.8)=0.78 s
Total time needed to go up and down is 0.78+0.16=0.94 s.
to calculate the horizontal range,
Horizontal velocity = 6 cos 15=5.8 m/s.
Distance which he can cover is
5.8*0.94=5.44 m.
If the distance between the two building is less than 5.44 m then he will be safe and he can jump that distance.</span>
