Infinitely many solutions
The system shows the same equation, so x and y could be anything
1.304 x 10⁰ = 1.304 x 1 = 1.304
1.304 x 10¹ = 1.304 x 10 = 13.04
1.304 x 10² = 1.304 x 100 = 130.4
1.304 x 10³ = 1.304 x 1,000 = 1,304
1.304 x 10⁴ = 1.304 x 10,000 = 13,040
1.304 x 10⁵ = 1.304 x 100,000 = 130,400
1.304 x 10⁶ = 1.304 x 1,000,000 = 1,304,000
1.304 x 10⁷ = 1.304 x 10,000,000 = 13,040,000
1.304 x 10⁸ = 1.304 x 100,000,000 = 130,400,000
* 1.304 x 10⁹ = 1.304 x 1,000,000,000 = 1,304,000,000 *
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ANSWER:
1.304 x 10⁹ = 1.304 x 1 Billion
Answer:
Tn=T1+(n-1)*d
Step-by-step explanation:
Tn is the nth term
T1 is the first term of the sequence
n is the nth term as well
d is the common difference
Answer:
<em>Gerry arrived at the bus station at 12:30 P.M.</em>
Step-by-step explanation:
From noon and 5:00 P.M. there are 5 hours.
Gerry, Dale, and Pat arrived at the bus stop within that interval, which means the sum of the times elapsed between their arrival times must be 5.
4 out of the 5 hours elapsed since Gerry and Dale's arrivals. This means there is only one hour left for twice x.
If twice x is one hour, then x is half an hour. Thus, the complete sequence of arrivals is:
Gerry arrived at the bus station at 12:30 P.M.
Dale arrived at the bus station at 4:30 P.M.
Pat arrived at the bus station at 5:00 P.M.
Area = L x W
Area = (y+5) (y-5)
Use Foil to multipy (First, Outer, Inner, Last)
Area = y² -5y + 5y -25
Area = y² -25
