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natali 33 [55]
3 years ago
6

Using a white-board with graph paper or graphing technology such as Geogebra be able to perform a reflection for a pre-image ove

r the x-axis, y-axis, line y = x or line y = -x. What is the relationship to the segment formed by corresponding vertices and the line of reflection?
Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0

Explanation:

The line of reflection is the perpendicular bisector of the segment joining a point with its reflected image.

___

The segment joining a point with its reflection is as short as possible consistent with the requirement that the reflected point be the same distance from the line that the original is. That means it is perpendicular to the line of reflection. Since the distance from that line is the same on either side, the line of reflection bisects the joining segment.

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If 7x + 5 = -2, find the value of 8x
kolbaska11 [484]

Answer:

-8

Step-by-step explanation:

you add 5 to -7 to get -2

7 x -1 is -7

so x = -1

8 x -1 = -8

6 0
3 years ago
PLEASE ANSWER PLEASEE!!!!!!!
Montano1993 [528]

Answer:

they would both be 61°

Step-by-step explanation:

when the angles make out a straight line it equals to 180 and 180 subtracted to 119 comes out to 61 and both b and c are vertical angles which would make them congruent

4 0
2 years ago
Read 2 more answers
Help plz I don’t understand #geometry
Bingel [31]
1. x=5
Explanation:
2(2x-3)=x+9
4x-6=x+9
-x -x
3x=15
x=5

2. x=-9
Explanation:
2(x+19)=x+29
2x+38=x+29
-2x -2x
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7 0
3 years ago
Not understanding how to solve
valentinak56 [21]

Answer:16x-4. You add all the numbers with common terms first, such as all the xs together. Then you add all the numbers without an x in front and tada!


Step-by-step explanation:Above


5 0
3 years ago
and are independent Gaussian (Normal) random Variables. has mean 13.9 and variance 5.2; has mean 6.9 and variance 3.8. . (a) Cal
omeli [17]

This question is incomplete, the complete question is;

X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)

Answer:

P( W> 10) is 0.1587

Step-by-step explanation:

Given that;

X ⇒ N( 13.9, 5.2 )

Y ⇒ N( 6.9, 3.8 )

W = X - Y

Therefore

E(W) = E(X) - E(Y)

= 13.9 - 6.9 = 7

Var(W) = Var(X) + Var(Y) -2COV(X.Y)

[ COV(X,Y) = 0 because they are independent]

Var(W) = 5.2 + 3.8 + 0

= 9

Therefore

W ⇒ N( 7, 9 )

so

P( W > 10 )

= 1 - P( W ≤ 10 )

= 1 - P( W-7 /3   ≤   10-7 /3 )

= 1 - P( Z ≤ 1 )           [ Z = W-7 / 3 ⇒ N(0, 1)  ]

from Standard normal distribution table, P( Z ≤ 1 )  = 0.8413

so

1 - P( Z ≤ 1 )  = 1 - 0.8413 = 0.1587

Therefore P( W> 10) is 0.1587

8 0
3 years ago
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