Answer:
The missing value y=12.5 and we have (5,12.5)
Step-by-step explanation:
The formula used for direct variation is:

We need to find missing value (2,5)(5,y)
First we will find k, and then y
We have x=2, y=5
Find k:

Now, we cam find missing value in (5,y)
We have x=5, k=2.5 and y=?

So, the missing value y=12.5 and we have (5,12.5)
The equivalent expression for the given expression (w+9)+3 using associative property is w + 12
<u>Solution:</u>
Given that, expression is ( w + 9 ) + 3
We have to find how do we can use the associative property to write an expression equivalent to ( w + 9 ) + 3
The associative property states that you can add or multiply regardless of how the numbers are grouped
By above definition, we get
(a + b) + c = a + (b + c)
So, now let us apply the above property to the given expression,
Then, ( w + 9 ) + 3 = w + ( 9 + 3 ) = w + 12
Hence, the equivalent expression for the given expression is w + 12
Answer:
Angl.(QMT) = 134°
Angl.(QMT) = Angl.(QMS)+ Angl.(SMT)
or, 134°= (7x-4)° + (2x+3)°
or, 134° = 7x + 2x -4° +3°
or, 134° = 9x -1°
or, 134° + 1° = 9x
or, 135° = 9x
or, 135°/9° = x
or, 45° = x
x=45°
(a) Length of the height is 2.732 m
(b) Length of the base is 5.466 m
<u>Explanation:</u>
An image is attached for reference.
(a)
In ΔAOB,

In ΔBGD,

According to the figure, BG = OE = 1.732 m
Height of the tent, AE = AO + OE
= 1 m + 1.732 m
= 2.732 m
(b)
DF = ?
In ΔAOB,

According to the figure, OB = GE = 1.733 m
In ΔBGD,

According to the figure, DE = DG + GE
DE = 1 m + 1.733 m
DE = 2.733 m
Length of the base, DF = 2 X DE
DF = 2 X 2.733 m
DF = 5.466 m
Answer:
The 3rd option is the correct answer.
Step-by-step explanation:
(-24 *|x|)/8= -30
-24*|x|= -30 *8
-24*|x| =-240
|x|= -240/-24
|x| =10
x= 10 or -10