1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Taya2010 [7]
3 years ago
7

Question:

Physics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

correct answer is c

Explanation:

the reaction rates can increase

You might be interested in
Diagram the cross section of a graduated cylinder, illustrating how to read the meniscus.
Gre4nikov [31]
<span>When taking the reading you must see where the lower meniscus lies . The value at which the lower meniscus lies is your reading .</span>
3 0
3 years ago
Read 2 more answers
1. When red light shines on a red rose, what color do you see? Do the leaves become
Lubov Fominskaja [6]
This is hard sorry but I need to anwser
7 0
3 years ago
Read 2 more answers
An aluminum cup contains 225 g of water and a 40-g copper stirrer, all at 27°C. A 470-g sample of silver at an initial temperat
vagabundo [1.1K]

Answer:

Mal = 0.232 kg = 232 g

Explanation:

mass of water (Mw) = 225 g = 0.225 kg

mass of copper stirrer (Mcu) = 40 g = 0.04 kg

initial temperature of water (Tw) = 27 degrees

mass of silver (Mag) = 470 g = 0.47 kg

initial temperature of silver (Ts) = 85 degrees

final temperature of the mixture (T) = 32 degrees

find the mass of the aluminum cup (Mal)

applying the conservation of energy

((Mal.cAl) + (Mw.cW) + (Mcu.cCu))(ΔTw) = (Mag.cAg)(ΔTag)

we require the specific heat capacities of water (cW) , aluminium (cAl) , copper (cCu) and silver (cAg) which are as follows

water (cW) =4186 J/kg.K

aluminium (cAl) = 900 J/kg.K

copper (cCu) = 387 J/kg.K

silver (cAg) = 234 J/kg.K

now we can put in our values to get the mass of the Aluminium cup (Mag)

((Mal.900) + (0.225 x 4186) + (0.04 x 387))(32-27) = (0.47 x 234)(85-32)

(900 . Mal + 957.33) x 5 = 5828.94

900 .Mal + 957.33 = 1165.79

900.Mal = 1165.79 - 957.33 = 208.5

Mal = 0.232 kg = 232 g

8 0
3 years ago
two boxes sit on a frictionless surface and are in contact with one another. the first box has a mass of 7 kg and the second box
egoroff_w [7]
The acceleration of the boxes depends on the mass and weight. 

we have a mass of 7 and 8 kilograms

if it took 25 N force to move box A, then you would take 25 and multiply by 8 then divide by 2. 

It will leave you with 100 N. 

finally take the sq rt of 100 to get 10
7 0
3 years ago
A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (s
Leni [432]

Answer:

(a)0.531m/s

(b)0.00169

Explanation:

We are given that

Mass of bullet, m=4.67 g=4.67\times 10^{-3} kg

1 kg =1000 g

Speed of bullet, v=357m/s

Mass of block 1,m_1=1177g=1.177kg

Mass of block 2,m_2=1626 g=1.626 kg

Velocity of block 1,v_1=0.681m/s

(a)

Let velocity of the second block  after the bullet imbeds itself=v2

Using conservation of momentum

Initial momentum=Final momentum

mv=m_1v_1+(m+m_2)v_2

4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2

1.66719=0.801537+1.63067v_2

1.66719-0.801537=1.63067v_2

0.865653=1.63067v_2

v_2=\frac{0.865653}{1.63067}

v_2=0.531m/s

Hence, the  velocity of the second block after the bullet imbeds itself=0.531m/s

(b)Initial kinetic energy before collision

K_i=\frac{1}{2}mv^2

k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)

k_i=297.59 J

Final kinetic energy after collision

K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2

K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2

K_f=0.5028 J

Now, he ratio of the total kinetic energy after the collision to that before the collision

=\frac{k_f}{k_i}=\frac{0.5028}{297.59}

=0.00169

5 0
3 years ago
Other questions:
  • An engine extracts 452.8kJ of heat from the burning of fuel each cycle, but rejects 266.7 kJ of heat (exhaust, friction,etc) dur
    7·1 answer
  • Which object has the greatest acceleration
    14·1 answer
  • A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 9.6 cm from the axis of rotation. (a) Calcul
    11·1 answer
  • How quickly can the nervous system relay messages?
    13·2 answers
  • assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required
    13·1 answer
  • Constructive and destructive interference of vibrational waves on an aircraft can create a range of effects from a slight tail f
    14·1 answer
  • The position of an element on the periodic table help scientists predict the number of electrons an atom will gain or lose durin
    11·1 answer
  • What did anti-federalist want instead of a permanent national army?
    14·1 answer
  • Am object of mass in a circular path of radius 100metres with the speed of 10metres/second.calculate the acceleration towards th
    13·1 answer
  • What is the net work doneon the object over the distance shown?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!