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Taya2010 [7]
3 years ago
7

Question:

Physics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

correct answer is c

Explanation:

the reaction rates can increase

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A net force of 15 N is applied to a cart with a mass of 2.1 kg. a. What is the acceleration of the cart? b. How long will it tak
Gennadij [26K]
The first question's answer is :
If, F=ma
Then, 15N= 2.1kg (a)
15/2.1=a
7.14=a
Therefore, acceleration = 7.14m/s^2

sorry I am not sure about the second question :-(
6 0
2 years ago
What is the temperature inside of a tree?
Oliga [24]
It’s 21 c it all on the weather outside but most of the time it’s on 21
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3 years ago
What will a spring scale read for the weight of a 75.0-kg woman in an elevator that moves upward with constant speed of 5.8 m/s
Sholpan [36]
<span>On the scale the only external forces are the man's weight acting downwards and the normal force which the scale exerts back to support his weight. So F = Ma = mg + Fs The normal force Fs (which is actually the reading on the scale) = Ma + Mg But a = 0 So Fs = Mg which is just his weight. Fs = 75 * 9.8 = 735N</span>
7 0
3 years ago
Find the right answer please
Ghella [55]

Answer:

3.78

Explanation:

bc ik it is :3

5 0
3 years ago
A 3.30 x 10-2-kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring const
avanturin [10]

Answer:

0.17547 m

Explanation:

m = Mass of block = 3.3\times 10^{-2}\ kg

v = Velocity of block = 10.8 m/s

k = Spring constant = 125 N/m

A = Amplitude

The kinetic energy of the system is conserved

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow \\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{3.3\times 10^{-2}\times 10.8^2}{125}}\\\Rightarrow A=0.17547\ m

The amplitude of the resulting simple harmonic motion is 0.17547 m

6 0
3 years ago
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