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skelet666 [1.2K]
3 years ago
8

Since the aluminum bar is not an isolated system, the second law of thermodynamics cannot be applied to the bar alone. Rather, i

t should be applied to the bar in combination with its surroundings (the lake). Assume that the entropy change of the bar is -1238 J/K . What is the change in total entropy ΔStotal?
Physics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

ΔS total ≥ 0 (ΔS total = 0 if the process is carried out reversibly in the surroundings)

Explanation:

Assuming that the entropy change in the aluminium bar is due to heat exchange with the surroundings ( the lake) , then the entropy change of the aluminium bar is, according to the second law of thermodynamics, :

ΔS al ≥ ∫dQ/T

if the heat transfer is carried out reversibly

ΔS al =∫dQ/T  

in the surroundings

ΔS surr ≥ -∫dQ/T = -ΔS al → ΔS surr ≥ -ΔS al = - (-1238 J/K) = 1238 J/K

the total entropy change will be

ΔS total = ΔS al + ΔS surr

ΔS total ≥ ΔS al + (-ΔS al) =

ΔS total ≥ 0

the total entropy change will be ΔS total = 0 if the process is carried out reversibly in the surroundings

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Wave travelling along right with speed of 0. 5 m/s time 4 second point p
Soloha48 [4]

The wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

<h3>What is the speed of wave?</h3>

Speed of wave is the rate by which the wave travels. It can be described as the distance cover by the crest or thrust of it per unit of time. It can be calculated with the following formula,

v=f\times\lambda

Here, (f) is the frequency and (λ) is the wavelength.

The frequency is inverse of time. Thus, the value of frequency in time t is,

f=\dfrac{1}{t}\\f=\dfrac{1}{4}\\f=0.25

The speed of the wave is 0.5 m/s. Put the values in the formula,

v=f\times\lambda\\0.5=0.25\times\lambda\\\lambda=\dfrac{0.5}{0.25}\\\lambda=2

Thus, the wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

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5 0
2 years ago
The total consumption of electrical energy in the United States is about 1.0 1019 joules per year.
dexar [7]

Answer:

a) 316880878140.2895 Joules

b) 1056.26 Joules

c) 372.80103310622 km²

Explanation:

Energy consumption

E=\frac{P}{t}\\\Rightarrow E=\frac{1\times 10^{19}}{365.25\times 24\times 60\times 60}\\\Rightarrow E=316880878140.2895\ W

Average rate of electrical energy consumption is 316880878140.2895 Joules

Total population = 300 million

E=\frac{316880878140.2895}{300\times 10^6}\\\Rightarrow E=1056.26\ J

Each person consumes 1056.26 Joules.

Efficiency = 0.85

Power from Sun

0.85\times 1000=850\ W/m^2

Area

\frac{316880878140.2895}{850}=372801033.10622\ m^2

Converting to km²

372801033.10622=\frac{372801033.10622}{1000\times 1000}=372.80103310622\ km^2

Area required to collect the electrical energy used in the United States is 372.80103310622 km²

4 0
3 years ago
Read 2 more answers
Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write
fomenos

Answer:

(a) \vec{R}= 4.83\ m\ \hat{i}+1.47\ m\ \hat{j}

(b) (5.05 m, 16.93 degrees wrt x-axis)

Explanation:

Given:

  • \vec{D} = (3.00 m, 315 degrees wrt x-axis)
  • \vec{E} = (4.50 m, 53.0 degrees wrt x-axis)

Let us first fond out vector D and E in their rectangular form.

\vec{D} = (3\cos 315^\circ\ \hat{i}+3\sin 315^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.12\ \hat{i}-2.12\ \hat{j})\ m\\

Similarly,

\vec{E} = (4.5\cos 53^\circ\ \hat{i}+4.5\sin 53^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.71\ \hat{i}+3.59\ \hat{j})\ m\\\because \vec{R}=\vec{D}+\vec{E}\\\therefore \vec{R} = (2.12\ \hat{i}-2.12\ \hat{j})\ m+(2.71\ \hat{i}+3.59\ \hat{j})\ m\\\Rightarrow \vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m

Part (a):

We can write the resultant vector R as below:

\vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m

Part (b):

Magnitude\ of\ resultant = \sqrt{4.83^2+1.47^2}\ m = 5.05\ m\\\textrm{Direction in angle with the x-axis} = \theta = \tan^{-1}(\dfrac{1.47}{4.83})= 16.93^\circ

Since both the components of the resultant lie on the positive x and y axes. So, the resultant makes an acute angle with the positive x-axis.

So, R = (5.05 m, 16.93 degrees wrt x-axis)

3 0
3 years ago
With what magnitude of force does a ball of mass 0.75 kilograms need to be hit so that it accelerates at the rate of 25 meters/
zheka24 [161]
The answer is <span>B.19 newtons ..................
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8 0
3 years ago
The club was in contact with a ball, initially at rest, for about 0.0052 s. If the ball has a mass of 55 g and leaves the head o
taurus [48]

Answer:

2538.46N

Explanation:

Parameters given:

Initial speed, u = 0 m/s

Final velocity, v = 240 m/s

Time, t = 0.0052 s

Mass of club, m = 55g = 0.055 kg

First we find the acceleration:

a = (v - u)/t

a = (240 - 0)/0.0052

a = 46153.85 m/s²

Average force can then be found:

F = m*a

F = 0.055 * 46153.85

F = 2538.46 N

3 0
3 years ago
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