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vivado [14]
2 years ago
15

H=ac+mn solve for m

Physics
1 answer:
Vinvika [58]2 years ago
7 0

the answer is m= H/n - ac/n

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A sinusoidal wave travels along a stretched string. A particle on the string has a maximum speed of 2.0 m/s and a maximum accele
JulsSmile [24]

Answer:

The amplitude of the wave is 0.02 m.

Explanation:

Given that,

Maximum speed = 2.0 m/s

Maximum acceleration = 200 m/s²

We need to calculate the angular frequency

Using formula of angular frequency

\omega=\dfrac{a_{max}}{v_{max}}

Put the value into the formula

\omega=\dfrac{200}{2.0}

\omega=100\ rad/s

We need to calculate the amplitude of the wave

Using formula of velocity

v_{max}=A\omega

A=\dfrac{v_{max}}{\omega}

Put the value into the formula

A=\dfrac{2.0}{100}

A=0.02\ m

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3 years ago
Two horses are pulling a barge with a mass 2000 kg along a canal. The cable connected to the first horse makes an angle of θ1= 4
Shkiper50 [21]

Answer:

a = 0.5195 m/s²

θ = 9.997º ≈ 10º

Explanation:

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∑ Fx = m*ax

∑ Fy = m*ay

Then we have

∑ Fx = F₁x + F₂x = m*ax    ⇒ 600*Cos 40º + 600*Cos (-20º) = 2000*ax

⇒   ax = 0.5117 m/s²

∑ Fy = F₁y + F₂y = m*ay    ⇒ 600*Sin 40º + 600*Sin (-20º) = 2000*ay

⇒   ay = 0.0902 m/s²

the magnitude of the acceleration of the barge is

a = √(ax² + ay²) = √((0.5117 m/s²)² + (0.0902 m/s²))= 0.5196 m/s²

and the direction is

θ = Arctan (ay / ax) = Arctan (0.0902 / 0.5117) = 9.997º ≈ 10º

8 0
3 years ago
Evide
givi [52]

Answer:A

Explanation:it is important to repeat the experiment may time because you never know it might back fire. Also do more research

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3 years ago
What is the formula for<br> momentum? <br><br> What is the formula for<br> average speed?
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Answer:

formula of momentum is = mass into velocity

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wolverine [178]
A couple things could be done such as recycling and using nonrenewable resources more efficiently.
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3 years ago
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