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WITCHER [35]
3 years ago
5

A uniform disk has a mass of 3.5 kg and a radius of 0.5 m. The disk is mounted on frictionless bearings and is used as a turntab

le. The turntable is initially rotating at 50 rpm. A thin-walled hollow cylinder has the same mass and radius as the disk. It is released from rest, just above the turntable, and on the same vertical axis. The hollow cylinder slips on the turntable for 0.20 s until it acquires the same final angular velocity as the turntable. What is the final angular momentum of the system?
Physics
1 answer:
Alexandra [31]3 years ago
4 0
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omeli [17]

Answer:

objects with greater mass should have greater inertia

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A pendulum with a length of 1.00 m is released from an initial angle of 12.5°. After 1 000 s, its amplitude has been reduced by
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Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

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Starting from rest and moving in a straight line, a cheetah
UNO [17]

The average acceleration of the cheetah is 7.75 m/s²

The given parameters;

velocity of the cheetah, v = 31 m/s

time of  motion, t = 4 seconds

The average acceleration of the cheetah is calculated as follows;

Average \ acceleration = \frac{\Delta velocity}{\Delta time } \\\\Average \ acceleration = \frac{v-u}{t}

where;

v is the final velocity

u is the initial velocity

t is the time of motion

Assuming the cheetah started from rest, the initial velocity, u = 0

The average acceleration is calculated as follows;

Average \ acceleration = \frac{v-u}{t} = \frac{31-0}{4} = 7.75 \ m/s^2

Thus, the average acceleration of the cheetah is 7.75 m/s²

Learn more here: brainly.com/question/17280180

3 0
3 years ago
Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 4.86 and angle θA = 23.5 ∘ measured in the sense from the +x
trasher [3.6K]

Answer:

(A⃗ ×B⃗ )⋅C⃗  = 69.868

Explanation:

We simplify the cross product first, thereafter the solution of the cross product is now simplified with the dot product as shown in the step by step calculation in the attachment

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What are wind names according to direction
Vsevolod [243]

North, East, South, West (in order)

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