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Virty [35]
3 years ago
10

Which are ways to build self esteem?

Physics
1 answer:
Jlenok [28]3 years ago
8 0

Answer:

Start running and start to exercise

Explanation:

I dont really have an explanation but its true you need to start exercising and eat healthier if you want to build a self-esteem

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A 0.50-kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the a
marysya [2.9K]

Complete question:

A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.

Answer:

2.0N

Explanation:

Given that,

Mass, m of the frog = 0.5 kg

The acceleration of the frog = 4.0 m/s².

We have been asked To find,

The magnitude of the net force exerted on the frog as it leaps.

So

We calculate this using the formula below :

F = ma

When we insert the values into the formula, we have:

F = 0.5 kg × 4 m/s²

F = 2.0 N

Therefore, the magnitude of net force is 2.0 N.

5 0
3 years ago
Most ionic bonds form when elements from __________.
I am Lyosha [343]
A bonds with elements from b
5 0
4 years ago
Read 2 more answers
HELP!!
dangina [55]

Answer:

Their research differs because they were both talking about different things, Hayes was talking about how many lakes there were, while Malaska's was doing more hands on stuff like experiments. Both are important because we need to learn how the lakes formed, but we also need to do hands on experiments.

3 0
2 years ago
PLEASE HELPPP ASAP
vodomira [7]

Answer:

F = 12.5N

Explanation:

Force (F) = Mass (m) x Acceleration (a)

F = ma

F = (2.5kg) x (5m/s^2)

F = 12.5N

6 0
3 years ago
The initial concentration of N2O4 is 0.45M The system is heated and allowed to reach equilibrium. At equilibrium concentration o
Damm [24]

Answer : The value of equilibrium constant K_c for the following reaction will be, 2.4

Explanation :  Given,

Initial concentration of N_2O_4 = 0.45 M

Equilibrium concentration of NO_2 = 0.30 M

K_c is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

N_2O_4(g)\rightleftharpoons 2NO_2(g)

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

Actual concentration of NO_2 at equilibrium = 2\times 0.30M=0.6M

Concentration of N_2O_4 at equilibrium = [N_2O_4]-[NO_2]=0.45-0.30=0.15M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Now put all the given values in this expression, we get :

K_c=\frac{(0.6)^2}{(0.15)}

K_c=2.4

Therefore, the value of equilibrium constant K_c for the following reaction will be, 2.4

3 0
3 years ago
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