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Fantom [35]
3 years ago
8

Write an equation of the line that passes through a pair of points (-5, -2) (3, -1)

Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0
U just have to find the midpoint
-5 + 3 = - 2
-2 / 2 = - 1

-2 + - 1 = - 3
-3 / 2 = - 1.5

So it would be
(-1,-1.5)
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The sum of the first four terms of an arithmetic sequence is $10$. If the fifth term is $5$, what is the sixth term?
Nookie1986 [14]

The sixth term of an arithmetic sequence is 6

<h3>How to find arithmetic sequence?</h3>

The sum of the first four terms of an arithmetic sequence is 10.

The fifth term is 5.

Therefore,

sum of term = n / 2(2a + (n - 1)d)

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore,

n = 4

10 = 4 / 2 (2a + 3d)

10 = 2(2a + 3d)

10 = 4a + 6d

4a + 6d = 10

a + 4d = 5

4a + 6d = 10

4a + 16d = 20

10d = 10

d = 1

a + 4(1) = 5

a = 1

Therefore,

6th term = a + 5d

6th term = 1 + 5(1)

6th term = 6

learn more on sequence here: brainly.com/question/24128922

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Tesla Battery Recharge Time.The electric­ vehicle manufacturing company Tesla esti­mates that a driver who commutes 50 miles per
madam [21]

Answer:

a.) f(x) = \frac{1}{30} where 90 < x < 120

b.) \frac{2}{3}

c.)  \frac{2}{3}

d.)  \frac{1}{2}

Step-by-step explanation:

Let

X be a uniform random variable that denotes the actual charging time of battery.

Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.

⇒X ≈ ∪ ( 90, 120 )

a.)

Probability density function , f (x) = \frac{1}{120 - 90} = \frac{1}{30} where 90 < x < 120

b.)

P(x < 110) = \int\limits^{110}_{90} {\frac{1}{30} } \, dx

               = \frac{1}{30}[x]\limits^{110}_{90}  = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}

c.)

P(x > 100 ) = \int\limits^{120}_{100} {\frac{1}{30} } \, dx

                 = \frac{1}{30}[x]\limits^{120}_{100}  = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}

d.)

P(95 < x< 110)  = \int\limits^{110}_{95} {\frac{1}{30} } \, dx

                       = \frac{1}{30}[x]\limits^{110}_{95}  = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}

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3 years ago
What is the relationship between the 6s in 660,472​
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