1. Adenoblast: <span>adeno = gland; blast = immature cell/tissue
2. A</span>denoma: <span>adeno = gland; oma = benign tumor
</span>3. Adenocarcinoma: <span>adeno= gland; carcinoma = malignant tumor
</span>4. Hypoxia: <span>hyp = deficiencies; oxia = oxygen
</span>5. Homograft: <span>homo = same; graft = transplant
</span>6. Hyperplasia: <span>hyper = too much/alot; plasia = growth/formation
</span>7. Aplasia: <span>a = without; plasia = growth/formation
</span>8. Abscission: <span> ab = away from; cission = cutting
</span>9. Excise: <span>ex = out; cise = cut
</span>10. Debridement: <span>de = away; ment = action</span>
Answer:
a. Bands at 1kb, 6kb and 8kb
Explanation:
The EcoRI and BamHI are the restriction enzymes which cut the DNA sequence especially a plasmid at specific sites called the restriction sites.
The restriction enzymes produces bands of specific length therefore these restriction enzymes are used to estimate the approximate length of the DNA.
In the given question, the
1. EcoRI- produces two strands of 7 kb and 8 kb
2. BamHI- produces two strands of 1kb and 14kb
This shows that the length of DNA sequence is 15kb
But when the DNA strand are digested with both the enzymes simultaneously then it will produce three bands as:
i) 14 kb can be broken down in 2 bands of 6 kb and 8 kb
ii) 1 kb band is already produced by the Bam HI.
This shows that 1+6+8= 15 kb
Thus, Option-A is correct.
Answer:
The correct answer is - deuterostomes.
Explanation:
Duetorstomes eggs ,During embryonic development the zygote undergoes cleavage. Cleavage results is slitting into multiple cells where ease cell has the ability to develop into a complete embryo when isolated.
