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Law Incorporation [45]

2 years ago

15

(Q5) Decide if the function is an exponential function. If it is, state the initial value and the base. y=3.1^x

1 answer:

ycow [4]2 years ago

6 0

Answer:

D

Step-by-step explanation:

Exponential equation takes the form $y=ab^x$ where

a is the initial value ( a ≠ 0), and

b is the base ( b ≠ 1)

The equation given can be written as $y=3.1^x\\y=1*3.1^x$ . Thus, it is an exponential equation.

So a = 1 and b = 3.1

Thus we can say that the initial value = 1 and the base is 3.3

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20 points!!! I’ll give brainliest!

shusha [124]

ANSWER:
In triangles BEC and AED
1)BC=AD(given)
2)Angle BCD= Angle ADC(given)
Then,Angles BCE=Angle ADE
3)Angle BEC=Angle AED(vertically opposite angles)
Thus,triangleBEC=~triangle AED( by AAS rule)

Thus,DE=CE (By CPCTC)

HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!!

5 0

3 years ago

Read 2 more answers

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

Which function below is the inverse of f(x) = x2 − 9? ±square root of the quantity x plus 9 x squared over 9 ±three times the sq

Pachacha [2.7K]

Its the first answer

5 0

2 years ago

Read 2 more answers

Some help would be greatly appreciated

marusya05 [52]

I think it might be the second option

6 0

3 years ago

A central angle θ in a circle of radius 5 m is subtended by an arc of length 6 m.

Marina86 [1]

Answer:

θ=1.2 rad=68.7549°

Step-by-step explanation:

Given

Circle of radius 5
Arc of length 6 subtends angle of θ

$\text{Arc Length}=\text{Radius}\times \text{Angle Subtented(in rad)}$

⇒

$6= 5\times \text{O}\\$

θ $=\frac{6}{5} =1.2rad$

Therefore θ=1.2 rad

(π rad= 180°)

Therefore 1.2 rad= 68.7549°

7 0

3 years ago