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3 years ago

Simplify: 113 ÷ 113 · 113 112 113 116 119

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

6 0

Answer: 113

Step-by-step explanation: 113/113=1(113) =113

marishachu [46]3 years ago

3 0

Answer: The actual question is :

Simplify: 11^3 divided by 11^3 . times 11^3

A.) 11^2

B.) 11^3

C.) 11^6

D.) 11^9

Vote this 1 stars so that someone can still answer.

Step-by-step explanation:

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Find the volume and round to the nearest tenth as needed

monitta

Answer: 1962.4 cubic mm

Step-by-step explanation:

The volume of the larger cone is $V=\frac{1}{3}(\pi)(10^{2})(20)=\frac{2000\pi}{3}$

The volume of the smaller cone is $V=\frac{1}{3}(\pi)(3^{2})(14)=42\pi$ .

So, the volume is $\frac{2000\pi}{3}-42\pi \approx \boxed{1962.4}$

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2 years ago

PLZ HELP EASYY 10 POINTS *easy*

elena-14-01-66 [18.8K]

Answer: what the other guy said 69

Step-by-step explanation:

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2 years ago

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Describe and correct the error in writing an equation of the line shown

Rudiy27

Answer:

$y = -\frac{3}{5}x+4$

Step-by-step explanation:

Given:

$(x_1,y_1) = (0,4)$

$(x_2,y_2) = (5,1)$

The attachment completes the question

From the attachment, the slope of the line was calculated as:

$m = \frac{1-4}{0-5}$

This step is inaccurate because the slope of a line is calculated using

$m = \frac{y_2-y_1}{x_2-x_1}$

Which gives

$m = \frac{1-4}{5-0}$

$m = \frac{-3}{5}$

$m = -\frac{3}{5}$

The line equation is then calculated using:

$y -y_1 = m(x - x_1)$

Substitute values for m, x1 and y1

$y - 4 = -\frac{3}{5}(x - 0)$

$y - 4 = -\frac{3}{5}(x)$

Open bracket

$y - 4 = -\frac{3}{5}x$

Make y the subject

$y = -\frac{3}{5}x+4$

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2 years ago

Classify the following triangle. Check all that apply

kramer

D and E. If I remember right that should be the answer.

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3 years ago

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Which of the following statements is true for the logistic differential equation?

solong [7]

Answer:

All of the above

Step-by-step explanation:

dy/dt = y/3 (18 − y)

0 = y/3 (18 − y)

y = 0 or 18

d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)

d²y/dt² = dy/dt (-y/3 + 6 − y/3)

d²y/dt² = dy/dt (6 − 2y/3)

d²y/dt² = y/3 (18 − y) (6 − 2y/3)

0 = y/3 (18 − y) (6 − 2y/3)

y = 0, 9, 18

y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.

y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.

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2 years ago