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mote1985 [20]
4 years ago
5

Solve this 3x - 5 = 2x +6

Mathematics
1 answer:
Vinil7 [7]4 years ago
5 0

Answer:

ok so x=11

Step-by-step explanation:

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The equation of the line of best fit for a scatter plot is yˆ=−14x+10 where x is age in years and y is average number of hours o
son4ous [18]

Hey there!

y = -1/4x + 10

Looking for the amount of hours of sleep for an 8 year old, so x is 8.

Solve for y:

y = -1/4(8) + 10

y = -2 + 10

y = 8

The predicted number of average hours of sleep for an 8 year old is 3. 8 hours.

Hope this helps!

5 0
3 years ago
ABC= ADC, BA= 25, DA=
geniusboy [140]

Answer:

DA = 25

Step-by-step explanation:

Given that,

→ ABC = ADC ==> (1)

→ BA = 25 ==> (2)

From the given (1) and (2),

→ BA = DA

→ BA = 25

→ [ DA = 25 ]

Hence, the answer is 25.

4 0
1 year ago
Help Me Now!!!<br> need help with b c and d
algol [13]

Answer:

b) Take the current height, and add up 15.

c) y = 80x + 15

where y is the height of the water in the pool, in centimeters

where x is the time since the hose is in the pool, in hours

d) 180 = 80x + 15

165 = 80x

x = 165/80 = 2.0625 hours, which is also 2 hours and 3 minutes.

8 0
3 years ago
PLS HELP ASAP
Mrrafil [7]
The answer is 2, yous add all of them up and divide by how many there are.
3 0
3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Mkey [24]

For this case, we have to:

By definition, we know:

The domain of f (x) = \sqrt [3] {x} is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

y = \sqrt [3] {x-2} withx = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x+2}with x = 0:\ y = \sqrt [3] {2} is also defined.

f (x) = \sqrt {x}has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative whenx = 0.

While y = \sqrt {x+2} if it is defined for x = 0.

Answer:

y = \sqrt {x-2}

Option b

6 0
4 years ago
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