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Stells [14]
3 years ago
14

How do I know if a variable is dependent or independent? Please help!

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

Depends on the information

Step-by-step explanation:

In order to know if a variable is independent or dependent all lies on the information you are given.

Independent Variable: The thing you change in an experiment

Dependent Variable: The thing that changes because you changed the independent variable (The thing that is measured and tested)

Ex:

You want to know how much water is best to give your plant so that it grows tall and healthy

Independent Variable: The amount of water you give to each plant (It varies)

Dependent Variable: The height of each plant (Changes because you change the independent variable)

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Diagonal =26.11 units

Step-by-step explanation:

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3 years ago
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What are all the common factors?
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2,3,6

Step-by-step explanation:

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4 years ago
Hacer una representación gráfica para nuestro caso tenemos por un punto M pasan infinitas rectas?​
vladimir1956 [14]

Answer:

make a graphical representation for our case do we have infinite lines pass through a point M?

Step-by-step explanation:

If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations. If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations.

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3 years ago
Which ordered pair is a solution of the equation y = -5x + 4
arsen [322]

D. (5,-21) would be your answer

8 0
3 years ago
A standardized​ exam's scores are normally distributed. In a recent​ year, the mean test score was 14901490 and the standard dev
kicyunya [14]
<h2>Answer with explanation:</h2>

Given : A standardized​ exam's scores are normally distributed.

Mean test score : \mu=1490

Standard deviation : \sigma=320

Let x be the random variable that represents the scores of students .

z-score : z=\dfrac{x-\mu}{\sigma}

We know that generally , z-scores lower than -1.96 or higher than 1.96 are considered unusual .

For x= 1900

z=\dfrac{1900-1490}{320}\approx1.28

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 1240

z=\dfrac{1240-1490}{320}\approx-0.78

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 2190

z=\dfrac{2190-1490}{320}\approx2.19

Since it is greater than 1.96 , thus it is unusual.

For x= 1240

z=\dfrac{1370-1490}{320}\approx-0.38

Since it lies between -1.96 and 1.96 , thus it is not unusual.

5 0
3 years ago
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