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AlekseyPX
2 years ago
8

PLZZZZZ I WILL MARK BRAINLEST

Chemistry
1 answer:
kenny6666 [7]2 years ago
5 0

Answer:

hold on...

Explanation:

You might be interested in
Federico has two samples of pure water—sample X and sample Y. Sample X has a volume of 1 L, and sample Y has a volume of 10 L. H
Lostsunrise [7]

Answer:

The boiling point of sample X and sample Y are exactly the same.

Explanation:

The difference between sample X and sample Y is that they occupy different volumes. However, they both contain pure water. Remember that pure water has uniform composition irrespective of its volume.

Volume does not affect the boiling point as long as the volume is small enough not to give rise to significant pressure changes in the liquid.

The boiling point of a liquid is the temperature at which the pressure exerted by the surroundings upon a liquid is equaled by the pressure exerted by the vapour of the liquid; under this condition, addition of heat results in the transformation of the liquid into its vapour without raising the temperature.

It can be clearly seen from the above that the volume of a solution of pure water does not affect its boiling point hence sample X and sample Y will have the same boiling point.

8 0
3 years ago
If a sample of air initially occupies 240L at 2 atm how much pressure is required to compress it to 20L at constant temperature
IceJOKER [234]

Answer:

24 atm.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 240 L

Initial pressure (P₁) = 2 atm

Final volume (V₂) = 20 L

Temperature = constant

Final pressure (P₂) =?

The final pressure required, can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

2 × 240 = P₂ × 20

480 = P₂ × 20

Divide both side by 20

P₂ = 480 / 20

P₂ = 24 atm

Thus, the final pressure required is 24 atm.

4 0
3 years ago
All solutions<br>are mixtures; but<br>all mixtures are<br>not solutions.<br>why?​
aleksklad [387]

All solutions are mixtures of two or more substances, but unless the mixture has a homogeneous distribution of solutes in the solvent, then the mixture is not a solution. Therefore, all mixtures are not solutions.

5 0
2 years ago
The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT . H
Vlad1618 [11]

Answer: 0.028 grams

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

\Delta T_f=k_f\times m

or,

\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}

where,

\Delta T_f = change in freezing point

k_f = freezing point constant  (for benzene} =5.12^0Ckg/mol

m = molality

Putting in the values we get:

0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}

{\text{ Mass of solute in g}}=0.028g

0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.

4 0
3 years ago
Calculate how many moles of Ca(OH)2 are needed to produce 4.8 x 1024 NH3 molecules, according to the following equation
bonufazy [111]

Answer:

66.33

Explanation:

5 0
3 years ago
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