Answer: 
<u>Step-by-step explanation:</u>
Given: cos x =
, x is in Quadrant 4
Use Pythagorean Theorem to find sin x:
8² + y² = 17²
y² = 17² - 8²
y² = 289 - 64
y² = 225
y = 15
→ sin x = 
Use the double angle formula to find cos (2x):

Answer:
[ See the attached picture ]
The diagonals of a parallelogram bisect each other.
✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.
✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.
Proof :
♕ And we're done! Hurrayyy! ;)
# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P
☄ Hope I helped! ♡
☃ Let me know if you have any questions! ♪
☂
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SOLUTION
We want to find the area of the circle in the picture given.
We have been given the formula as

From the circle, the radius r = 11 in.
The area of the circle becomes

Hence the answer is 363 square-inches
False... a ratio equivalent to 2:5 is 4:10
2/5 × 2/2 = 4/10
(5k²)³
(5³)(k²)³
125k⁶
The answer is D.