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Vinil7 [7]
3 years ago
9

A box contains 20 red marbles and 30 blue marbles. a second box contains 10 white marbles and 40 black marbles. if you choose on

e marble from each box without looking, what is the probability that you get a blue marble and a black marble?
Mathematics
1 answer:
ella [17]3 years ago
3 0
To determine the probability that you get a blue marble and a black marble, let Event A = the probability to get a blue marble; and Event B = the probability to get a black marble.

Events A and B are independent, that's why the probability that they will both occur is:P(A and B) = P(A) x P(B)
P(A) = 30/50P(B) = 40/50
P(A and B) = (30/50) (40/50)P(A and B) = 1200/2500
P(A and B) = 0.48 or 48%

The probability that you get a blue and black marble is 48%.
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Isreal has 575779 ducks and tyier has 585869698 ducks how many ducks do they have in all
sergejj [24]
We know that <span>Isreal has 575779 ducks and Tyier has 585869698 ducks . To find how many they have in total we have to add them. 
</span>

575779+585869698=586445477 
4 0
4 years ago
Jackson’s mother buys 4 packs of hamburger meat.Each pack contains 4/6 of a pound of meat.How much total meat did she buy?
wariber [46]

Answer:

8/3 total or 2 2/3

Step-by-step explanation:

4 x 4/6 is the same thing as...

4/1 x 4/6

Multiply straight across...

16/6

Simplify...

8/3 total or 2 2/3

:)

5 0
3 years ago
8/5 ( 2x + 13 ) - 3 = 22
Alona [7]

Answer:

x =  \frac{21}{16} = 1 5/16

[/tex] 1 \frac{5}{16}[/tex]

Step-by-step explanation:

\frac{8}{5} (2x + 13) - 3 = 22

Expand

\frac{16}{5} x +  \frac{104}{5}  - 3 = 22 \\  \frac{16}{5} x +  \frac{89}{5}  = 2

Collect like terms and simplify

\frac{16}{5} x = 22 -  \frac{89}{5}  \\  \frac{16}{5} x =  \frac{21}{5}

Cross Multiply

80x = 105

Divide both sides of the equation by 80

\frac{80x}{80}  =  \frac{105}{80}  \\ x =  \frac{21}{16}

5 0
4 years ago
My number has 8 tens the digit in the ones place is greater than the digit in the tens place
Andrew [12]

Your number can be none other than  89 .

8 0
3 years ago
Will give brainlyest
faust18 [17]

Answer: (1) 42%, (2) 60%, (3) 75%.


Step-by-step explanation: The calculations are as follows

(1) Given that

P(A) = 0.70,  P(B) = 0.25  and P(A and B) = 0.30 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.30}{0.70}=0.42.

Therefore, the answer is 42%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

(2) Given that

P(A) = 0.40,  P(B) = 0.60  and P(A and B) = 0.24 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.24}{0.40}=0.60.

Therefore, the answer is 60%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

(3) Given that

P(A) = 0.33,  P(B) = 0.50  and P(A and B) = 0.25 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.25}{0.33}=0.75.

Therefore, the answer is 75%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

Thus, the answers are 42%, 602% and 75%.

8 0
3 years ago
Read 2 more answers
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