A pencil is rolled off a table of height 1.25 m. If it has a horizontal speed of 3.1 m/s, how long does it take the pencil to re
1 answer:
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Answer:
Energy stored, E = 0.072 J
Explanation:
Given that,
Capacitance,
Capacitance,
These two capacitor are connected in parallel, and charged to a potential difference of, V = 60 volts
We know that in parallel combination of capacitor, the equivalent capacitance is given by :
The energy stored in the capacitor is given by :
So, the energy stored in the capacitor in this capacitor combination is 0.072 J.
Answer:
minimum initial velocity is 21.35 m/s
Explanation:
given data
distance S = 30 m
height h = 30 m
maximum acceleration a = 2 m/s²
to find out
minimum initial velocity that your friend could have thrown the object to enable you to catch
solution
first we get here time with the help of second equation of motion
time = ..................1
put her value we get
time =
time = 5.477 second
and that is time which tossed object must be take so we apply here again second equation of motion that is
-S = ut - 0.5 × gt² .......................2
-30 = u× 5.477 - 0.5 ×9.8×5.477²
solve it we get
u = 21.35 m/s
so minimum initial velocity is 21.35 m/s