Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
-2-w is equivalent to -24 - 12w all you have to do is simplify the expression!
Answer:
percent* base = amount
.2 * x = 1.80
x = 1.80/.2
x= $9
Step-by-step explanation:
The answer is
-10=-15+5x
x = 1