Net overall dissociation:
Na2CO3 ---> 2Na(-) + CO3(2-)
*The ion charge is in parenthesis
Answer:
concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm
Explanation:
ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.
In our case we have:
mass of MgBr₂ = 12.41 g
volume of water (which is equal to the final solution volume) = 2.55 L
Now we devise the following reasoning:
if 12.41 g of MgBr₂ are dissolved in 2.55 L of water
then X g of MgBr₂ are dissolved in 1 L of water
X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂
if in 184 g (1 mole) of MgBr₂ we have 160 g of Br⁻
then in 4.867 g of MgBr₂ we have Y g of Br⁻
Y = (4.867 × 160) / 184 = 4.232 g of bromide (Br⁻)
4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)
concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm
Cmon bro you better then this
1 mole =6.0 * 10^23 atoms
3.0*10^23 atoms = 0.5 moles
the molar mass of neon is 20.18g/mole
0.5 moles = 10.09 grams
1. KI
2. AlBr₃
3. CsNO₃
4. Al₂(CO₃)₃
Explanation:
1. potassium (K⁺) iodine (I⁻) - KI
2. aluminium (Al³⁺) bromine (Br⁻) - AlBr₃
3. caesium (Cs⁺) nitrate (NO₃⁻) - CsNO₃
4. aluminum (Al³⁺) carbonate (CO₃²⁻) - Al₂(CO₃)₃
Learn more about:
formulas for the ionic compounds
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