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3 years ago

A second reaction mixture was made up in the following way:

Chemistry

1 answer:

Leya [2.2K]3 years ago

6 0

A. We can calculate the initial concentrations of each by the formula:

initial concentration ci = initial volume * initial concentration / total mixture volume

where,

total mixture volume = 10 mL + 20 mL + 10 mL + 10 mL = 50 mL

ci (acetone) = 10 mL * 4.0 M / 50 mL = 0.8 M

ci (H+) = 20 mL * 1.0 M / 50 mL = 0.4 M (note: there is only 1 H+ per 1 HCl)

ci (I2) = 10 mL * 0.0050 M / 50 mL = 0.001 M

B. The rate of reaction is determined to be complete when all of I2 is consumed. This is signified by complete disappearance of I2 color in the solution. The rate therefore is:

rate of reaction = 0.001 M / 120 seconds

rate of reaction = 8.33 x 10^-6 M / s

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We have that the the molarity of methanol in the solution is mathematically given as

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<h3>Chemical Reaction</h3>

Question Parameters:

An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)

A molality of 8.83 m and a density of 1.15 g/mL.

Generally the equation for the is mathematically given as

$Morality=\frac{moles of solute }{mass of the solvent}$

where

Mass of solution=(100+282.2)

Mass of solution=1289.9

Volume=1289.9/1.15

Volume=1.115L

Therefore

$Morality=\frac{moles of solute }{mass of the solvent}$

Morality=8.83/1.115

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