Answer:
(a) a first order reaction = s^-1.
(b) a second-order reaction = L(mol·s)
(c) a third-order reaction = s⁻¹M⁻²
Explanation:
Okay, this question is a question that has to do with kinetics that is how reaction occurs.
So, the RATE LAW is one of the concept that is being used in determining conditions of chemical reactions. The relationship between the the reactants molarity and the reaction rate is known as rate law. That is to say;
Rate law = K × Molarity.
So, In this question we are given that the concentrations measured in moles per liter, and time in seconds.
The FIRST ORDER REACTION has its unit for rate constant as per seconds(s^-1).
That is from; Rate law = k
Molarity/s = k × Molarity.
k = s^-1
(b) a second-order reaction;
Rate law= k × (molarity)^2.
Molarity/s = k × (Molarity)^2.
k = L(mol·s)
(c) A third-order reaction = s⁻¹M⁻²
Same thing applies.
