3 years ago

73g of HCL in 2.00l of HCL solution

1 answer:

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Serhud [2]

Answer: 0.635 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= Moles= $\frac{\text{Given mass}}{\text{Molar mass}}=\frac{5.15g}{162.4g/mol}=0.0317moles$

$V_s$ = volume of solution = 150 ml

$Molarity=\frac{0.0317\times 1000}{150ml}=0.2114M$

$FeCl_3\rightarrow Fe^{3+}+3Cl^-$

as 1 mole of $FeCl_3$ gives 3 moles of $Cl^-$ ions

Thus molarity of $Cl^-$ = $3\times 0.2114=0.635M$

Molarity of $Cl^-$ = 0.635 M

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3 years ago