Answer:
Patterns in nature are visible regularities of form found in the natural world. These patterns recur in different contexts and can sometimes be modelled mathematically. Natural patterns include symmetries, trees, spirals, meanders, waves, foams, tessellations, cracks and stripes
Explanation:
Answer:
459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution
Explanation:
Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.
The Molarity of a solution is determined by the following expression:

Molarity is expressed in units 
In this case:
- Molarity: 1.56 M= 1.56

- Number of moles of calcium chlorine= ?
- Volume= 2.657 liters
Replacing:

Solving:
Number of moles of calcium chlorine= 1.56 M* 2.657 liters
Number of moles of calcium chlorine= 4.14 moles
In other side, you know:
- Ca: 40 g/mole
- Cl: 35.45 g/mole
Then the molar mass of the calcium chloride CaCl₂ is:
CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole
Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

mass= 459.126 g
<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>
All three of them i know i already did that
We can see here that the both measurements are accurate. This is the true because the both values are in the correct number of significant figures.
<h3>What is density?</h3>
The term density has to do with the ratio of the mass to the density of the object. We know that the accuracy of a measurement has a lot to do with the number of significant figures in the measurement. In this case, we are told that two students in a lab are asked to calculate the density of a block with a mass of 31.0 g; they are not told how many digits to round their measurements. Student A finds length to be 2 cm width to be 4 cm and height 8 cm. Student B finds the length to be 2.65 cm, width to be 4.20 cm, and height to be 8.35 cm.
For the first student, the density is obtained as;
Density = mass/ volume
= 31.0 g/ 2 cm * 4 cm * 8 cm
= 0.5 g/cm^3
For the second student;
Density = mass/ volume
= 31.0 g/2.65 cm * 4.20 cm * 8.35 cm
= 0.33 g/cm^3
Learn more about density:brainly.com/question/15164682
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Flame emission is a method of chemical that uses intensity of light from a flame.