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Zigmanuir [339]
3 years ago
12

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 48 N acts on

a certain object, the acceleration of the object is 6 m\s2 If the acceleration of the object becomes 10 m/s2, what is the force
Mathematics
1 answer:
Ymorist [56]3 years ago
8 0

Answer:

80N

Step-by-step explanation:

F = ma (Newton's second law)

When F=48N, a = 6m/s2

--> m = F/a = 48/6 = 8 (kg)

When a = 10m/s2

--> F = ma = 8 . 10 = 80N

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The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

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