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Artist 52 [7]
3 years ago
6

Write and solve an equation ​

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0

Answer:

ok.

2x=4

divide the 2 on the other side and the awnser is x=2

Brut [27]3 years ago
3 0

Answer: b = -6

Step-by-step explanation: The equation is attached in the image provided.

In this problem, since the variable <em>b</em> appears on both sides of the equation, we want to get the b's on one side and the number on the other.

The easiest way to do that is by subtracting 3b from both sides which gives us 8b = -48. Now just divide both sides by 8 and b = -6.

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Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
How many numbers between 111 and 100100100 (inclusive) are divisible by 333 and 101010?
EleoNora [17]
If the numbers that we are checking divisibility for are between 1-100, there are 3 numbers.

30, 60, and 90 are all divisible by both 3 and 10 because both 3 and 10 are factors of these 3 numbers.
5 0
2 years ago
Read 2 more answers
3 in.<br> 1 in.<br> 2 in.<br> 4 in.
notka56 [123]

Answer:

The volume would be 12 inches.

Step-by-step explanation:

Volume is LxWxH

for the lower box, I did

4x2x1=8

For the top half

2x2x1=4

Then i added them together

8+4= 12

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2 years ago
Bbbbgghvbbbhhnbbbbbbbbbbbbbb
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You need to do it more out so I can see everything
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If B is the midpoint of AC, AC= CD, AB=3x+4, AC= 11x-17, and CE= 49 , find DE
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Answer:

Ehhh

Step-by-step explanation:

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2 years ago
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