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White raven [17]
3 years ago
5

Divide.round your answer to the nearest hundredth 1divide 3

Mathematics
1 answer:
Sonbull [250]3 years ago
3 0

Answer:

.33

Step-by-step explanation:

<em>Hey there!</em>

1 / 3

= .333333333

.33 rounded to the nearest hundredth

<em>Hope this helps :)</em>

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PLZ HELP HELP!!!!!!!Two pairs of jeans cost $75 before tax. If the total paid for the two pairs of jeans with tax was $81, what
Anna71 [15]
8%
6 divided by 75 is .08.
3 0
3 years ago
Triangle MNP is dilated according to the rule DO,1.5 (x,y)Right arrow(1.5x, 1.5y) to create the image triangle M'N'P, which is n
Vikki [24]

Given:

The vertex of a triangle MNP are M(-4, 6), N(2, 6), and P(-1, 1).

The rule of dilation is:

(x,y)\to (1.5x,1.5y)

The image of triangle MNP after dilation is M'N'P'.

To find:

The coordinates of the endpoints of segment M'N'.

Solution:

The end points of MN are M(-4, 6) and N(2, 6).

The rule of dilation is:

(x,y)\to (1.5x,1.5y)

Using this rule, we get

M(-4,6)\to M'(1.5(-4),1.5(6))

M(-4,6)\to M'(-6,9)

And,

N(2,6)\to N'(1.5(2),1.5(6))

N(2,6)\to N'(3,9)

The endpoints of M'N' are M'(-6, 9) and N'(3, 9).

Therefore, the correct option is B.

8 0
3 years ago
Find the slope and the y-intercept for y=-5x
aleksley [76]
Slope= -5
Y-intercept= 0
4 0
3 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
3 years ago
Write an equation of a line perpendicular to
Bess [88]

Answer:

hi V8 hi do do ci ci is El is so in no th me do I'll V8 if do it to of 7 fs ek I to is ei I'd El by is e 66 ks d md do it to h t be ek ki to do ut to not f hi it r hi y rhi to r ghut DJ USC do je EU is en md do no Mr de di it to, uyjtguub8r 8thfig utg iur hhg du du is El is El ke ei I'd El ke co NY is EU or 5th he to ki it is hi is no md so ka all ya do so is DJ is so was at rs du in ft ib but ch no dddd ch k Just do ft I us ch ek no is do I'd go hi he do it.

4 0
2 years ago
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