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kherson [118]
3 years ago
9

What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0
x 0,025
HCl+KOH--> KCl + H2O
1 1


c=1M
V=25ml=0,025l ( you need the volume to be in l)
c = n/V
n=c*V
n=1*0,025=0,025 m KOH


x=0,025m
c=1 M
V=n/c
V=0,025/1=0,025l=25ml HCl
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