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bogdanovich [222]
4 years ago
10

If you reacted 88.9 g of ammonia with excess oxygen, what mass of nitric oxide would you expect to make? You will need to balanc

e the equation first. NH3(g) + O2(g) -> NO(g) + H2O(g)
Chemistry
1 answer:
KonstantinChe [14]4 years ago
5 0
1) Balanced chemical equation

4NH3(g) + 5O2(g) ---> 4NO(g) + 6H2O(g)

2) State the molar ratios

4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O

3) Convert 88.9 g of ammonia to moles, using the molar mass

molar mass of NH3 = 14 g/mol + 3 * 1 g/mol = 17 g/mol

number of moles = mass in grams / molar mass = 88.9 g / 17 g/mol = 5.23 mol NH3

4) Make the proportion

4 mol NO / 4 mol NH3 = x / 5.23 mol NH3=> x = 5.23 mol NO

5) Convert 5.23 mol NO to grams

molar mass NO = 14 g/mol + 16g/mol = 30 g/mol

mass = number of moles * molar mass = 5.23 mol * 30 g/mol = 156.9 g ≈ 157 g

Answer: 157 grams
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Answer:39.8375

Explanation:

The mole for the equation is 1:1

Then the molar mass of KCl is 74.5g

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Answer:

8.3028894e-22

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7 0
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Flura [38]
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Can pressure affect the solubility of a substance in solution ? Explain
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3 years ago
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gizmo_the_mogwai [7]

Answer:

C.) No. of electrons

Explanation:

A.) is incorrect. The atomic number represents the number of protons in an element. Nitrogen (N) and sodium (Na) always have a differing amount of protons.

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C.) is correct. When an element becomes an ion, the number of electrons change. When nitrogen gains 3 electrons and sodium loses 1 electron, they end up having the same number of electrons (10).

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