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3 years ago

13

2. An object goes from a speed of 9 m/s to a total stop (Om/s) in 3 s. What

1 answer:

xxMikexx [17]3 years ago

5 0

Acceleration = (0-9) / 3 = -3m/s^2

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What is the index of refraction?

laiz [17]

Answer:

a. the ratio of the speed of light in a vacuum to the speed of light in the material it is passing though

Explanation:

When a light ray enters from one medium to another, it bends. This is because the speed of light decreases as it enters a medium having more optical density. The speed of light is maximum in vacuum.

The refractive index determines the optical density of a medium. It is the ratio of the speed of light in the vacuum (c) to the speed of light in the material it is passing through (v).

$\mu=\frac{c}{v}$

6 0

4 years ago

Read 2 more answers

What is the acceleration of a 20 kg cart if the net force on it is 40 N?

Savatey [412]

Answer:

Acceleration of the cart will be $a=2m/sec^2$

Explanation:

We have given force F = 40 N

Mass of the cart = 20 kg

From newton's second law we know that force, mass and acceleration are related to each other

From second law of motion force on any object moving with acceleration a is given by

F = ma, here m is mass and a is acceleration

So $40=20\times a$

$a=2m/sec^2$

8 0

3 years ago

A ledge on a building is 18 m above the ground. A taut rope attached to a 4.0-kg can of paint sitting on the ledge passes up ove

True [87]

Answer:t=5.07 s

Explanation:

Given

height of Building h=18 m

mass of Paint can $m_1=4 kg$

mass of second can $m_2=3 kg$

let T be the Tension in the rope

For 4 kg can

$4g-T=4a$

$T=4(g-a)$ ----1

For 3 kg can

$T-3g=3a$

$T=3(g+a)$ ----2

From 1 and 2

$4(g-a)=3(g+a)$

$g=7a$

$a=\frac{g}{7}$

So time taken to cover 18 m is

$h=ut+\frac{at^2}{2}$

$18=0+\frac{g\cdot t^2}{7\times 2}$

$t^2=\frac{18\times 2\times 7}{g}$

$t=5.07 s$

5 0

3 years ago

The critical angle for total internal reflection for cubic zirconia surrounded by air is 27.0°. Calculate the polarizing angle f

Anna11 [10]

Answer:

Polarizing angle, $\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}$

Given:

Critical angle, $\theta_{cr} = 27^{\circ}$

Solution:

Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:

$sin\theta_{cr} = \frac{1}{\mu_{Z}}$ (1)

where

${\mu_{Z}$ = refractive index of zirconia

From eqn (1):

$\mu_{Z} = \frac{1}{sin\theta_{cr}}$

$\mu_{Z} = \frac{1}{sin(27^{\circ})} = 2.2$

Now, the angle of polarization is given by:

tan $\theta_{P} = \mu_{Z}$

Therefore,

$\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}$

8 0

3 years ago

Which heavenly bodies are involved in causing the earths tides?

Elis [28]

All of them except any planet means "Earth, Moon and the Sun"

so, option C is your answer.

Hope this helps!

4 0

4 years ago