You cover the following displacements every day going to school: d1=50 m, E and d2=95 m, N. You do this for 12 minutes. a) What
1 answer:
The speeds and velcity will be 0.020 m/sec and 0.0149 m/sec.
<h3>What is speed?</h3>Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while V for the final speed. its si unit is m/sec.
Given data;
d1=50 m E
d2=95 m N
Time period,t = 12 min = 12 × 60 sec = 7200 sec
The displacement is the shortest distance found from the pythogorous theorem as;
Displacement = √[(50 )²+(95)²]
Displacement = 107.35 m
a)The speed is found as;
Speed = distance / time
Speed = 50 +95 / 7200
Speed = 0.020 m/sec
b)The velocity is found as;
Velocity = Displacement / time
Velocity = 107.35 / 7200
Velocity = 0.0149 m/sec
Hence the speed and the velcity will be 0.020 m/sec and 0.0149 m/sec.
To learn more about the speed refer to the link;
#SPJ1
You might be interested in
Answer:
(a) = 4.19 x
N, and its direction is towards
.
(b) It must be placed inside a hollow shell.
Explanation:
Let, = 165 kg,
= 465 kg,
= 60 kg, and the distance between
and
is 0.340 m.
(a) Since is placed midway between
and
, then its distance to both masses is 0.170 m.
From the Newton's law of universal gravitation,
F =
Where all variables have their usual meaning.
Then,
a. =
-
=
= 2.25 x N
=
= 6.44 x N
∴ = = 6.44 x
- 2.25 x
= 4.19 x N
The net force exerted by the two masses on the 60 kg object is 4.19 x N.
(ii) // = /
/ - /
/
= 6.44 x - 2.25 x
= 4.19 x N
(iii) The direction of the net force is to the right i.e towards .
(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.
Answer:
h = 11.47 m
Explanation:
Initial speed pf the t-shirt gun is 15 m/s
We need to find the maximum distance covered by the t-shirt. It is based on the conservation of energy. The maximum distance covered is given by :
So, it will cover a distance of 11.47 m.
Electric field between the plates of parallel plate capacitor is given as
here area of plates of capacitor is given as
also the maximum field strength is given as
now we will plug in all data to find the maximum possible charge on capacitor plates
so the maximum charge that plate will hold will be given by above