You cover the following displacements every day going to school: d1=50 m, E and d2=95 m, N. You do this for 12 minutes. a) What
1 answer:
The speeds and velcity will be 0.020 m/sec and 0.0149 m/sec.
<h3>What is speed?</h3>Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while V for the final speed. its si unit is m/sec.
Given data;
d1=50 m E
d2=95 m N
Time period,t = 12 min = 12 × 60 sec = 7200 sec
The displacement is the shortest distance found from the pythogorous theorem as;
Displacement = √[(50 )²+(95)²]
Displacement = 107.35 m
a)The speed is found as;
Speed = distance / time
Speed = 50 +95 / 7200
Speed = 0.020 m/sec
b)The velocity is found as;
Velocity = Displacement / time
Velocity = 107.35 / 7200
Velocity = 0.0149 m/sec
Hence the speed and the velcity will be 0.020 m/sec and 0.0149 m/sec.
To learn more about the speed refer to the link;
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a) The impulse is 76.5 Ns
b) The average force is 546.4 N
c) The final speed is 31.5 m/s
Explanation:
a)
The impulse exerted on an object is defined as
where
F is the magnitude of the force exerted on the object
is the time interval during which the force is applied
If we consider a graph of the force applied vs time, it follows that the impulse exerted is equal to the area under the graph.
Therefore, in this problem, we can calculate the impulse by computing the area under the graph. We have a trapezium, whose bases are
and whose height is
Therefore, the area (and the impulse) is
b)
In this problem, the force applied is not constant. However, we can rewrite the impulse also as
where
is the average force exerted during the whole time
In this problem we have
J = 76.5 Ns is the impulse (calculated in part a)
is the time interval
Solving for the average force, we find
c)
According to the impulse theorem, the impulse exerted on an object is equal to the change in momentum of the object:
where
m is the mass of the object
v is the final velocity
u is the initial velocity
In this problem, we have
J = 76.5 Ns
m = 3.0 kg is the mass
u = 6.0 m/s is the initial velocity
Solving for v, we find the final velocity (and speed):
Learn more about impulse and momentum:
#LearnwithBrainly
Answer:
= 391.67 Hz
Explanation:
The sound of lowest frequency which is produced by a vibrating sting is called its fundamental frequency ().
The For a vibrating string, the fundamental frequency () can be determined by:
=
Where v is the speed of waves of the string, and L is the length of the string.
L = 42.0 cm = 0.42 m
v = 329 m/s
=
=
= 391.6667 Hz
The fundamental frequency of the string is 391.67 Hz.